Find the values of x and y.

The sum of the interior angles in a triangle is $180^\circ$. The interior angles are $80^\circ$, $60^\circ$, and $y$.

$$80^\circ + 60^\circ + y = 180^\circ$$ $$140^\circ + y = 180^\circ$$

Subtract $140^\circ$ from both sides:

$$y = 180^\circ - 140^\circ$$ $$y = 40^\circ$$

The value of $y$ is \boxed{\text{40^\circ}}.

The angle $x$ and the angle $y$ form a linear pair on a straight line. Angles on a straight line sum to $180^\circ$.

$$x + y = 180^\circ$$

Substitute the value of $y = 40^\circ$ into the equation:

$$x + 40^\circ = 180^\circ$$

Subtract $40^\circ$ from both sides:

$$x = 180^\circ - 40^\circ$$ $$x = 140^\circ$$

The value of $x$ is \boxed{\text{140^\circ}}.