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Determine the volume scale factor for similar 3D shapes given their volumes or linear dimensions.

Mathematics

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Here are the solutions to the practice exercises:

1. Two similar cones have volumes of 324 cm3324 \text{ cm}^3 and 96 cm396 \text{ cm}^3 respectively. Determine their volume scale factor.

  1. Identify the given volumes.

    Let V1=324 cm3V_1 = 324 \text{ cm}^3 and V2=96 cm3V_2 = 96 \text{ cm}^3.

  2. Calculate the ratio of the volumes.

    The volume scale factor is the ratio of the volumes.

    Volume scale factor=V1V2=32496\text{Volume scale factor} = \frac{V_1}{V_2} = \frac{324}{96}
  3. Simplify the ratio.

    32496=16248=8124=278\frac{324}{96} = \frac{162}{48} = \frac{81}{24} = \frac{27}{8}

    The volume scale factor is 278\boxed{\frac{27}{8}}.

    2. A scouts tent in the shape of a triangular prism has a cross-sectional area of 10 m210 \text{ m}^2 and a length of 5 m5 \text{ m}. Another similar tent has a cross-sectional area of 40 m240 \text{ m}^2 and length 10 m10 \text{ m}. Determine the volume scale factor.

  4. Identify the given dimensions for the two similar tents.

    For Tent 1: L1=5 mL_1 = 5 \text{ m}.
    For Tent 2: L2=10 mL_2 = 10 \text{ m}.

  5. Determine the linear scale factor (kk).

    The linear scale factor is the ratio of corresponding lengths.

    k=L2L1=10 m5 m=2k = \frac{L_2}{L_1} = \frac{10 \text{ m}}{5 \text{ m}} = 2
  6. Calculate the volume scale factor.

    The volume scale factor is the cube of the linear scale factor (k3k^3).

    Volume scale factor=k3=(2)3=8\text{Volume scale factor} = k^3 = (2)^3 = 8

    The volume scale factor is 8\boxed{8}.

    3. A model of a cylindrical water tank has a radius of 10.5 cm10.5 \text{ cm} and a height of 15 cm15 \text{ cm}. Its actual radius is 210 cm210 \text{ cm}. Determine:
    a. the volume of the actual water tank. (Take π=3.142\pi = 3.142)
    b. the volume scale factor.

    a) The volume of the actual water tank.

  7. Identify the dimensions of the model and the actual tank.

    Model: rm=10.5 cmr_m = 10.5 \text{ cm}, hm=15 cmh_m = 15 \text{ cm}.
    Actual: $r_a =

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