Were is 4,2 and 4,3 4,4 4,5

$P(\text{Cameras Installed}) = P(C) = \frac{100}{200} = \frac{1}{2}$
$P(\text{Vandalism | Cameras Installed}) = P(V|C) = \frac{10}{100} = \frac{1}{10}$

The probability is $\boxed{\frac{1}{20}}$.

$P(\text{No Cameras Installed}) = P(NC) = \frac{100}{200} = \frac{1}{2}$
$P(\text{Vandalism | No Cameras Installed}) = P(V|NC) = \frac{15}{100} = \frac{3}{20}$

The probability is $\boxed{7.5\%}$.

To compare $\frac{1}{10}$ and $\frac{3}{20}$, we can express $\frac{1}{10}$ as $\frac{2}{20}$.
Since $\frac{3}{20} > \frac{2}{20}$, the probability of vandalism is higher when no cameras are installed.
The group of community hubs with a higher risk of vandalism is hubs with no cameras installed. This is because the probability of vandalism given no cameras ($P(V|NC) = \frac{3}{20}$) is greater than the probability of vandalism given cameras ($P(V|C) = \frac{1}{10} = \frac{2}{20}$).