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((x+1) + (x+7))/(3) + (x)/(2) = 5

Mathematics

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1.
We need to solve the equation x+13+x+73+x2=5\frac{x+1}{3} + \frac{x+7}{3} + \frac{x}{2} = 5.

  1. Combine the fractions with the same denominator.

    (x+1)+(x+7)3+x2=5\frac{(x+1) + (x+7)}{3} + \frac{x}{2} = 5 2x+83+x2=5\frac{2x+8}{3} + \frac{x}{2} = 5
  2. Find a common denominator for 3 and 2, which is 6.

    Multiply the entire equation by 6.

    6(2x+83)+6(x2)=6×56 \left( \frac{2x+8}{3} \right) + 6 \left( \frac{x}{2} \right) = 6 \times 5 2(2x+8)+3x=302(2x+8) + 3x = 30
  3. Distribute and simplify the equation.

    4x+16+3x=304x + 16 + 3x = 30 7x+16=307x + 16 = 30
  4. Isolate xx.

    7x=30−167x = 30 - 16 7x=147x = 14 x=147x = \frac{14}{7} x=2x = 2

    The correct option is 2) 2.
    The final answer is 2\boxed{\text{2}}.

    2.
    We need to solve the equation x3−79=209\frac{x}{3} - \frac{7}{9} = \frac{20}{9}.

  5. Add 79\frac{7}{9} to both sides of the equation.

    x3=209+79\frac{x}{3} = \frac{20}{9} + \frac{7}{9} x3=20+79\frac{x}{3} = \frac{20+7}{9} x3=279\frac{x}{3} = \frac{27}{9}
  6. Simplify the fraction on the right side.

    x3=3\frac{x}{3} = 3
  7. Multiply both sides by 3 to solve for xx.

    x=3×3x = 3 \times 3 x=9x = 9

    The correct option is 3) 9.
    The final answer is 9\boxed{\text{9}}.

    3.
    We need to solve the equation 3x2+4=4x−11\frac{3x}{2} + 4 = 4x - 11.

  8. Multiply the entire equation by 2 to eliminate the fraction.

    2(3x2+4)=2(4x−11)2 \left( \frac{3x}{2} + 4 \right) = 2(4x - 11) 3x+8=8x−223x + 8 = 8x - 22
  9. Gather xx terms on one side and constant terms on the other side.

    8+22=8x−3x8 + 22 = 8x - 3x 30=5x30 = 5x
  10. Solve for xx.

    x=305x = \frac{30}{5} x=6x = 6

    The correct option is 3) 6.
    The final answer is 6\boxed{\text{6}}.

    4.
    We need to solve the equation 2x−8−3x=x−122x - 8 - 3x = x - 12.

  11. Combine like terms on the left side of the equation.

    (2x−3x)−8=x−12(2x - 3x) - 8 = x - 12 −x−8=x−12-x - 8 = x - 12
  12. Gather xx terms on one side and constant terms on the other side.

    −8+12=x+x-8 + 12 = x + x 4=2x4 = 2x
  13. Solve for xx.

    x=42x = \frac{4}{2} x=2x = 2

    The correct option is 2) 2.
    The final answer is 2\boxed{\text{2}}.

    5.
    We need to solve the equation 7y3−4=2y6+8\frac{7y}{3} - 4 = \frac{2y}{6} + 8.

  14. Simplify the fraction 2y6\frac{2y}{6}.

    7y3−4=y3+8\frac{7y}{3} - 4 = \frac{y}{3} + 8
  15. Multiply the entire equation by 3 to eliminate the fractions.

    3(7y3−4)=3(y3+8)3 \left( \frac{7y}{3} - 4 \right) = 3 \left( \frac{y}{3} + 8 \right) 7y−12=y+247y - 12 = y + 24
  16. Gather yy terms on one side and constant terms on the other side.

    7y−y=24+127y - y = 24 + 12 6y=366y = 36
  17. Solve for yy.

    y=366y = \frac{36}{6} y=6y = 6

    The final answer is 6\boxed{\text{6}}.

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