You correctly rewrote 4^b as 22b in the denominator.

Mathematics

ScanSolve AI Answer

Answer

12b+1\frac{1}{2^b + 1}

Step-by-step solution

5 steps

Your work is correct, Bonga🤍!

You have correctly simplified the expression.

  1. You correctly rewrote 4b4^b as 22b2^{2b} in the denominator.

    2b−122b−1\frac{2^b - 1}{2^{2b} - 1}
  2. You introduced the substitution k=2bk = 2^b, which is a good way to simplify the appearance of the expression.

    k−1k2−1\frac{k - 1}{k^2 - 1}
  3. You correctly factored the denominator k2−1k^2 - 1 using the difference of squares formula, a2−c2=(a−c)(a+c)a^2 - c^2 = (a - c)(a + c).

    k−1(k−1)(k+1)\frac{k - 1}{(k - 1)(k + 1)}
  4. You correctly cancelled the common term (k−1)(k - 1) from the numerator and denominator.

    1k+1\frac{1}{k + 1}
  5. You substituted k=2bk = 2^b back into the expression to get the final answer.

    12b+1\boxed{\frac{1}{2^b + 1}}

    ✅ Correct!

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