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A vehicle moving at 5m/s covered a distance of 75m before coming to stop. How long did it take to cover this distance?

Physics

ScanSolve AI Answer

Answer

30 s30 \, \text{s}

Step-by-step solution

3 steps
  1. Identify the given values from the problem.

    Initial velocity, u=5 m/su = 5 \, \text{m/s}
    Final velocity, v=0 m/sv = 0 \, \text{m/s} (since the vehicle comes to a stop)
    Distance covered, s=75 ms = 75 \, \text{m}
    We need to find the time, tt.

  2. Select the appropriate kinematic equation.

    The equation that relates initial velocity (uu), final velocity (vv), distance (ss), and time (tt) is:

    s=u+v2ts = \frac{u+v}{2}t
  3. Substitute the given values into the equation and solve for tt.

    75 m=5 m/s+0 m/s2t75 \, \text{m} = \frac{5 \, \text{m/s} + 0 \, \text{m/s}}{2}t 75=52t75 = \frac{5}{2}t 75=2.5t75 = 2.5t

    To find tt, divide both sides by 2.5:

    t=752.5t = \frac{75}{2.5} t=30 st = 30 \, \text{s}

    The time it took to cover this distance is 30 s30 \, \text{s}.

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