Fig below shows a mass suspended by wire strops from fixed points A and B. Determine the force in strop AC and the force in strop BC.

The mass $m = 500 \, \text{kg}$.
The acceleration due to gravity $g = 9.81 \, \text{m/s}^2$.
The weight $W$ is given by:

Let $T_1$ be the force in strop AC and $T_2$ be the force in strop BC. The weight $W$ acts vertically downwards.
The angles are measured between the lines of action of the forces:

• Angle between $T_1$ (strop AC) and $T_2$ (strop BC) is given as $95^\circ$.
• Angle between $T_1$ (strop AC) and $W$ (vertical downward force): Strop AC makes an angle of $30^\circ$ with the horizontal. The vertical force $W$ is $90^\circ$ from the horizontal. So, the angle between $T_1$ and $W$ is $30^\circ + 90^\circ = 120^\circ$.
• Angle between $T_2$ (strop BC) and $W$ (vertical downward force): Strop BC makes an angle of $55^\circ$ with the horizontal. The vertical force $W$ is $90^\circ$ from the horizontal. So, the angle between $T_2$ and $W$ is $55^\circ + 90^\circ = 145^\circ$.

Lami's Theorem states that for three forces in equilibrium, each force is proportional to the sine of the angle between the other two forces.