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Calculate the potential difference across a 10 resistor carrying current of 2 A.

Physics

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:
Calculate the potential difference across a 10 Ω\Omega resistor carrying current of 2 A.

  1. Identify the given values.

    Resistance R=10ΩR = 10 \Omega
    Current I=2 AI = 2 \text{ A}

  2. Use Ohm's Law to calculate the potential difference VV.

    The formula for Ohm's Law is V=IRV = IR.

    V=(2 A)×(10Ω)V = (2 \text{ A}) \times (10 \Omega) V=20 VV = 20 \text{ V} Potential difference V=20 V\boxed{\text{Potential difference } V = 20 \text{ V}}

    :
    The potential difference across a 3 Ω\Omega resistor is 12 V. What is the current flowing?

  3. Identify the given values.

    Resistance R=3ΩR = 3 \Omega
    Potential difference V=12 VV = 12 \text{ V}

  4. Use Ohm's Law to calculate the current II.

    Rearranging Ohm's Law V=IRV = IR for II:

    I=VRI = \frac{V}{R} I=12 V3ΩI = \frac{12 \text{ V}}{3 \Omega} I=4 AI = 4 \text{ A} Current I=4 A\boxed{\text{Current } I = 4 \text{ A}}

    :
    Find the potential difference across a conductor of resistance 2 Ω\Omega if the charge of 180 C flows for 2 minutes.

  5. Identify the given values and convert units.

    Resistance R=2ΩR = 2 \Omega
    Charge Q=180 CQ = 180 \text{ C}
    Time t=2 minutes=2×60 s=120 st = 2 \text{ minutes} = 2 \times 60 \text{ s} = 120 \text{ s}

  6. Calculate the current II using the formula I=QtI = \frac{Q}{t}.

    I=180 C120 sI = \frac{180 \text{ C}}{120 \text{ s}} I=1.5 AI = 1.5 \text{ A}
  7. Use Ohm's Law to calculate the potential difference VV.

    The formula for Ohm's Law is V=IRV = IR.

    V=(1.5 A)×(2Ω)V = (1.5 \text{ A}) \times (2 \Omega) V=3 VV = 3 \text{ V} Potential difference V=3 V\boxed{\text{Potential difference } V = 3 \text{ V}}

    :
    A current of 4 A flows through an electric kettle. The p.d. across it is 8 V. Find the resistance.

  8. Identify the given values.

    Current I=4 AI = 4 \text{ A}
    Potential difference V=8 VV = 8 \text{ V}

  9. Use Ohm's Law to calculate the resistance RR.

    Rearranging Ohm's Law V=IRV = IR for RR:

    R=VIR = \frac{V}{I} R=8 V4 AR = \frac{8 \text{ V}}{4 \text{ A}} R=2ΩR = 2 \Omega Resistance R=2Ω\boxed{\text{Resistance } R = 2 \Omega}

    :
    The potential difference across a 2 kΩ\Omega resistor is 4 V. Determine the current flowing in the circuit.

  10. Identify the given values and convert units.

    Resistance R=2 kΩ=2×103Ω=2000ΩR = 2 \text{ k}\Omega = 2 \times 10^3 \Omega = 2000 \Omega
    Potential difference V=4 VV = 4 \text{ V}

  11. Use Ohm's Law to calculate the current II.

    Rearranging Ohm's Law V=IRV = IR for II:

    I=VRI = \frac{V}{R} I=4 V2000ΩI = \frac{4 \text{ V}}{2000 \Omega} I=0.002 AI = 0.002 \text{ A}

    This can also be expressed in milliamperes:

    I=2×10−3 A=2 mAI = 2 \times 10^{-3} \text{ A} = 2 \text{ mA} Current I=0.002 A (or 2 mA)\boxed{\text{Current } I = 0.002 \text{ A (or } 2 \text{ mA)}}
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