This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
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You're on a roll — Step 1: Solve Question 319. The question asks which statement is correct regarding the force between two charges q_1 and q_2 separated by a distance d. According to Coulomb's Law, the electrostatic force (F) between two point charges is directly proportional to the product of their magnitudes and inversely proportional to the square of the distance between them. The correct option is (গ) F (q_1 q_2)/(d^2). Step 2: Solve Question 320. The question asks which of the given statements is correct regarding fundamental forces. Statement i: মহাকর্ষ বল একটি দুর্বল বল। (Gravitational force is a weak force.) This is true; it is the weakest fundamental force. Statement iv: সবল নিউক্লিয় বলের পাল্লা খুব কম। (The range of strong nuclear force is very short.) This is also true; the strong nuclear force acts over very short distances within the nucleus. The correct option is (ঘ) i ও iv. Step 3: Solve Question 321. The question asks for the unit of Coulomb's constant (k). From Coulomb's Law, F = k (q_1 q_2)/(d^2). Rearranging for k, we get k = (F d^2)/(q_1 q_2). Substituting the units: k = N · m^2C · C = N · m^2 · C^-2 The correct option is (খ) Nm^2C^-2. Step 4: Solve Question 322. The question asks for the electric field strength (E) when a 5 C charge experiences a 1.5 N force. Electric field strength is defined as force per unit charge. E = (F)/(q) Substitute the given values: E = 1.5 N5 C = 0.3 N/C Among the given options, 0.33 N/C is the closest value. The correct option is (ঘ) 0.33 N/C. Step 5: Solve Question 323. First, calculate the electric field strength (E) at the point where a 40 C charge experiences a 160 N force. E = (F_1)/(q_1) = 160 N40 C = 4 N/C Now, calculate the force (F_2) on a 50 C charge (q_2) at the same point. F_2 = E × q_2 = 4 N/C × 50 C = 200 N The correct option is (ঘ) 200. Step 6: Solve Question 324. The question asks for the electric potential (V) at a point if 800 J of work (W) is done to move a 16 C charge (q) from a zero potential reference point to that point. Electric potential is defined as work done per unit charge. V = (W)/(q) Substitute the given values: V = 800 J16 C = 50 V The correct option is (খ) 50 V. Step 7: Solve Question 325. Given a capacitor with capacitance C = 25 = 25 × 10^-6 F and charge Q = 3.5 × 10^-4 C. i. ক্যাপাসিটরটি চার্জিত আছে। (The capacitor is charged.) This is true because there is a charge Q on its plates. ii. এর বিভব 14 V। (Its potential is 14 V.) Calculate potential V = (Q)/(C). V = 3.5 × 10^-4 C25 × 10^-6 F = (3.5)/(25) × 10^2 V = 0.14 × 100 V = 14 V This statement is true. iii. এর সঞ্চিত শক্তি 2.45 mJ। (Its stored energy is 2.45 mJ.) Calculate stored energy U = (1)/(2)QV. U = (1)/(2) × (3.5 × 10^-4 C) × (14 V) = 24.5 × 10^-4 J = 2.45 × 10^-3 J = 2.45