What is the pressure exerted by a weight of 20 N, whose surface area in contact with the floor is 2 m?

Physics

ScanSolve AI Answer

Answer

10 Pa10\ \text{Pa}

Step-by-step solution

3 steps

The pressure exerted is 10 Pa.

  1. Identify the formula for pressure

    Pressure (PP) is defined as Force (FF) per unit Area (AA).

    P=FAP = \frac{F}{A}
  2. Substitute the given values

    Given Force (Weight) F=20 NF = 20\ \text{N}
    Given Area A=2 m2A = 2\ \text{m}^2

    P=20 N2 m2P = \frac{20\ \text{N}}{2\ \text{m}^2}
  3. Calculate the pressure

    P=10 N/m2P = 10\ \text{N/m}^2

    The unit N/m² is also known as Pascal (Pa).

    P=10 PaP = 10\ \text{Pa}

    The final answer is 10 Pa10\ \text{Pa}.

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