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A microscope has a field of view with a diameter of 4.6 cm. If 21.74 cells are counted along the diameter under X1000 magnification, what is the actual diameter of one cell in micrometers?

Biology

ScanSolve AI Answer

Answer

46 mm\text{46 mm}

21.74

2.12μm2.12 \mu \text{m}

Step-by-step solution

5 steps
  1. Solve part a).

    The length of the white line is given as 4.6 cm4.6 \text{ cm}. To convert this to millimeters, we use the conversion factor 1 cm=10 mm1 \text{ cm} = 10 \text{ mm}.

    4.6 cm×10 mm1 cm=46 mm4.6 \text{ cm} \times \frac{10 \text{ mm}}{1 \text{ cm}} = 46 \text{ mm}

    The diameter of the field of view is 46 mm\boxed{\text{46 mm}}.

  2. Solve part b).

    The question asks for the number of cells found along the diameter. The image provided for part a) only shows a white line in a black box, not cells. However, based on the student's subsequent work for part c), a value of 21.74 cells is used. We will proceed with this value.
    The number of cells found along the diameter is 21.74\boxed{21.74}.

  3. Solve part c).

    To determine the actual diameter of one cell, we use the formula:

    Actual diameter of one cell=Diameter of field of viewNumber of cells×Magnification\text{Actual diameter of one cell} = \frac{\text{Diameter of field of view}}{\text{Number of cells} \times \text{Magnification}}

    From part a), the diameter of the field of view is 46 mm46 \text{ mm}.
    From part b), the number of cells is 21.74.
    The magnification is given as X1000X1000.

    Substitute the values into the formula:

    Actual diameter of one cell=46 mm21.74×1000\text{Actual diameter of one cell} = \frac{46 \text{ mm}}{21.74 \times 1000} Actual diameter of one cell=46 mm21740\text{Actual diameter of one cell} = \frac{46 \text{ mm}}{21740} Actual diameter of one cell≈0.0021159 mm\text{Actual diameter of one cell} \approx 0.0021159 \text{ mm}

    To express this in micrometers (μm\mu \text{m}), we use the conversion factor 1 mm=1000μm1 \text{ mm} = 1000 \mu \text{m}:

    0.0021159 mm×1000μm1 mm≈2.1159μm0.0021159 \text{ mm} \times \frac{1000 \mu \text{m}}{1 \text{ mm}} \approx 2.1159 \mu \text{m}

    Rounding to two decimal places:
    The actual diameter of one cell is 2.12μm\boxed{2.12 \mu \text{m}}.

  4. Solve part d).

    A weakness of the process of estimating cell size is that the cells are not always uniform in size, and estimating the exact number of cells along the diameter can be subjective, especially if cells are not perfectly aligned or are partially visible.

  5. Solve question 7.

    The image shows a plant cell where the cell membrane has pulled away from the cell wall, and the cytoplasm has shrunk. This process is known as plasmolysis. Plasmolysis occurs when a plant cell is placed in a hypertonic solution, meaning the solution has a higher solute concentration than the cell's cytoplasm. Water moves out of the cell by osmosis, causing the cell to lose turgor and the protoplast (cell membrane and its contents) to shrink away from the cell wall.

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