This business/management problem is solved step by step below, with detailed explanations to help you understand the method and arrive at the correct answer.
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You're on a roll — here are the solutions to your math questions. Q2. a)* Step 1: Calculate the profit. Profit = Selling Price - Cost Price Profit = GH₵650 - GH₵500 = GH₵150 Step 2: Calculate the percentage profit. Percentage Profit = ProfitCost Price × 100\% Percentage Profit = GH₵150GH₵500 × 100\% Percentage Profit = 0.3 × 100\% = 30\% The percentage profit is 30\%. b)* Step 1: Identify the principal, rate, and time. Principal (P) = GH₵1000 Rate (R) = 5% per annum Time (T) = 3 years Step 2: Use the simple interest formula. Simple Interest (SI) = (P × R × T)/(100) SI = (1000 × 5 × 3)/(100) Step 3: Calculate the simple interest. SI = (15000)/(100) = GH₵150 The simple interest is GH₵150. Q3. a)* The marks obtained by 10 students are: 12, 15, 10, 18, 20, 15, 17, 19, 14, 10. i. Step 1: Sum all the marks. Sum = 12 + 15 + 10 + 18 + 20 + 15 + 17 + 19 + 14 + 10 = 150 Step 2: Calculate the mean. Mean = Sum of marksNumber of students = (150)/(10) = 15 The mean mark is 15. ii. Step 1: Identify the frequency of each mark. 10 appears 2 times. 12 appears 1 time. 14 appears 1 time. 15 appears 2 times. 17 appears 1 time. 18 appears 1 time. 19 appears 1 time. 20 appears 1 time. Step 2: Determine the mark(s) that appear most frequently. Both 10 and 15 appear 2 times, which is the highest frequency. The mode is 10 and 15. b)* Step 1: Identify the highest and lowest marks from the data. Highest mark = 20 Lowest mark = 10 Step 2: Calculate the range. Range = Highest mark - Lowest mark Range = 20 - 10 = 10 The range of the data is 10. Q4. a)* Step 1: Understand the relationship between bearings. If the bearing of B from A is , then the bearing of A from B is + 180^ if < 180^, or - 180^ if > 180^. Step 2: Apply the rule for the given bearing. Given bearing of B from A = 060^. Since 060^ < 180^, we add 180^. Bearing of A from B = 060^ + 180^ = 240^ The bearing of A from B is 240^. b)* Step 1: Visualize the movement as a right-angled triangle. The man walks 5 km East (one leg of the triangle) and 12 km North (the other leg of the triangle). The distance from the starting point is the hypotenuse. Step 2: Use the Pythagorean theorem (a^2 + b^2 = c^2). Let a = 5 km and b = 12 km. Let c be the distance from the starting point. c^2 = (5 km)^2 + (12 km)^2 c^2 = 25 km^2 + 144 km^2 c^2 = 169 km^2 Step 3: Solve for c. c = sqrt(169 km)^2 c = 13 km The distance from the starting point is 13 km. What's next?