Solve 128base10 to base 8

April 7, 2026Chemistry

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Answer

128_{10} = 200_8

Step-by-step solution

4 steps

Divide 128 by 8.
$128 \div 8 = 16 \text{ remainder } 0$
Divide the quotient (16) by 8.
$16 \div 8 = 2 \text{ remainder } 0$
Divide the quotient (2) by 8.
$2 \div 8 = 0 \text{ remainder } 2$
Read the remainders from bottom to top.
The remainders are 2, 0, 0.
$128_{10} = \boxed{200_8}$

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