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22g of hydrated Sodium Sulphate, Na2SO4 · X H2O were heated to a constant mass of 1.42g, determine the value of X in the formula.
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9 steps29) 3.22g of hydrated Sodium Sulphate, were heated to a constant mass of 1.42g, determine the value of X in the formula. ().
Calculate the mass of anhydrous sodium sulphate and water.
Mass of hydrated salt =
Mass of anhydrous salt () =
Mass of water lost = Mass of hydrated salt - Mass of anhydrous saltCalculate the molar mass of and .
Molar mass of
Molar mass ofCalculate the moles of anhydrous sodium sulphate and water.
Moles of
Moles ofDetermine the mole ratio to find X.
Ratio of moles : moles
Therefore, .
30) 20 of 2 M Sulphuric (IV) acid reacted completely with 3.2 g of WOH () Calculate the R.A.M of W in the formula WOH.
Write the balanced chemical equation.
Sulphuric (IV) acid is . Assuming WOH is a monobasic hydroxide, the reaction is:
Calculate the moles of .
Volume of
Molarity ofCalculate the moles of WOH using the mole ratio from the balanced equation.
From the equation, 1 mole of reacts with 2 moles of WOH.
Calculate the molar mass of WOH.
Mass of WOH =
Calculate the R.A.M of W.
Molar mass of OH =
1) The figure below shows part of non-luminous flame.
(a) (i) Describe an experiment that would confirm that region labeled A is not suitable for heating.
- Hold a thin copper wire or a wooden splinter horizontally across the non-luminous flame, ensuring that one part of the wire/splinter is in region A (the inner blue cone) and another part is in the outer blue cone (the hottest part of the flame).
- Observe which part of the wire glows red first or which part of the splinter chars first. The part in the outer blue cone will glow red or char much faster than the part in region A, confirming that region A is cooler and thus not suitable for heating.
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