A) Predict the outcome of mixing aqueous solutions

Here are the solutions to the problems:

3.a) Predict the outcome of mixing aqueous solutions

i) Iron (II) sulphate with acidified potassium manganese (VII)
The standard electrode potential for $\text{MnO}_4^-/\text{Mn}^{2+}$ is $+1.52 \text{ V}$, and for $\text{Fe}^{3+}/\text{Fe}^{2+}$ is $+0.77 \text{ V}$. Since $\text{MnO}_4^-$ has a more positive standard reduction potential, it will be reduced, acting as the oxidizing agent. $\text{Fe}^{2+}$ will be oxidized to $\text{Fe}^{3+}$.
Outcome: *$\text{Fe}^{2+}$ is oxidized to $\text{Fe}^{