A reaction is 2 H2 + O2 -> 2 H2O. If 4.0 g of H2 reacts completely with excess O2, what mass of H2O is produced? Show the worked solution.

Chemistry

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Answer

36 g of H2O is produced.

Step-by-step solution

5 steps

Worked Solution:

  1. Calculate the molar masses

    • Molar mass of H2 = 2 * 1.008 g/mol = 2.016 g/mol
    • Molar mass of H2O = (2 * 1.008 g/mol) + 15.999 g/mol = 18.015 g/mol
  2. Convert the given mass of H2 to moles

    • Moles of H2 = Mass of H2 / Molar mass of H2
    • Moles of H2 = 4.0 g / 2.016 g/mol = 1.984 mol H2
  3. Use the mole ratio from the balanced equation to find moles of H2O

    • From the equation 2 H2 + O2 -> 2 H2O, the mole ratio of H2 to H2O is 2:2, or 1:1.
    • Moles of H2O = Moles of H2 = 1.984 mol H2O
  4. Convert moles of H2O to mass

    • Mass of H2O = Moles of H2O * Molar mass of H2O
    • Mass of H2O = 1.984 mol * 18.015 g/mol = 35.74 g H2O
  5. Round to appropriate significant figures

    • The given mass (4.0 g) has two significant figures, so the answer should also be rounded to two significant figures.
    • Mass of H2O = 36 g
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