A solution of HCl with a concentration of 4×10 mol L has a pH value of

Chemistry

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Answer

C

3.21\boxed{\text{3.21}}

Step-by-step solution

2 steps

Here's the solution for question 3:

3. The question asks for the pH of an HCl solution with a concentration of 4×10−44 \times 10^{-4} mol L−1^{-1}.

  1. Determine the concentration of hydrogen ions.

    HCl is a strong acid, meaning it dissociates completely in water. Therefore, the concentration of H+^+ ions is equal to the concentration of HCl.

    [H+]=4×10−4 mol L−1[\text{H}^+] = 4 \times 10^{-4} \text{ mol L}^{-1}
  2. Calculate the pH using the formula pH=−log⁡[H+]\text{pH} = -\log[\text{H}^+].

    pH=−log⁡(4×10−4)\text{pH} = -\log(4 \times 10^{-4}) pH=−(log⁡4+log⁡10−4)\text{pH} = -(\log 4 + \log 10^{-4}) pH=−(0.602−4)\text{pH} = -(0.602 - 4) pH=−(−3.398)\text{pH} = -(-3.398) pH=3.398\text{pH} = 3.398

    Rounding to two decimal places, the pH is approximately 3.40.

    Comparing this to the given options, (c) 3.21 is the closest value.

    The correct option is (c) 3.21\boxed{\text{3.21}}.

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