This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
Here are the solutions to the chemistry questions from the image: Question 11: The question describes an organic compound that: "Evolve steamy white fumes with PCl_5" - This indicates the presence of a hydroxyl (-OH) group, characteristic of alcohols or carboxylic acids. The reaction produces HCl gas, which forms steamy white fumes. "Equally evolve a colourless gas with sodium carbonate" - This indicates the presence of a carboxylic acid (-COOH) group, as carboxylic acids react with carbonates to produce carbon dioxide (CO_2) gas, which is colourless. Alcohols do not react with sodium carbonate. Combining these two observations, the compound must be a carboxylic acid. Let's examine the options: A. CH_3CH_2CH_2OH (Propan-1-ol) is an alcohol. It reacts with PCl_5 but not with sodium carbonate. B. CH_3CH=CH(OH) (Propen-1-ol) is an enol, which is generally unstable. It has an -OH group but is not a carboxylic acid. C. CH_3CH_2CH_2Cl (1-Chloropropane) is a haloalkane. It does not have an -OH group and does not react with sodium carbonate to produce gas. D. CH_3CH_2COOH (Propanoic acid) is a carboxylic acid. It contains an -OH group (within the -COOH) that reacts with PCl_5 and a -COOH group that reacts with sodium carbonate to produce CO_2. The final answer is D. Last free one today — make it count tomorrow, or type /upgrade for unlimited.