This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
Step 1: Andika nambari zote katika equation kama nguvu za base ya kawaida, ambayo ni 2. Tunayo 4 = 2^2, 8 = 2^3, na 32 = 2^5. Hivyo, equation inakuwa: (2^2)^3x × 2^3 = (2^-5)^2x-3 Tumia sheria ya exponents (a^m)^n = a^mn: 2^2 × 3x × 2^3 = 2^-5(2x-3) 2^6x × 2^3 = 2^-10x+15 Step 2: Rahisisha upande wa kushoto wa equation kwa kutumia sheria ya exponents a^m × a^n = a^m+n. 2^6x+3 = 2^-10x+15 Step 3: Linganisha exponents kwa sababu bases ni sawa. 6x+3 = -10x+15 Step 4: Tatua kwa x. Ongeza 10x pande zote mbili: 6x + 10x + 3 = 15 16x + 3 = 15 Toa 3 pande zote mbili: 16x = 15 - 3 16x = 12 Gawanya kwa 16: x = (12)/(16) Rahisisha sehemu: x = (3)/(4) Jibu la mwisho ni (3)/(4). 3 done, 2 left today. You're making progress.