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Balance the chemical equation: Fe + Cl2 -> FeCl3

Chemistry

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Answer

2Fe+3Cl2→2FeCl32\text{Fe} + 3\text{Cl}_2 \rightarrow 2\text{FeCl}_3

Step-by-step solution

6 steps
  1. Assign variables to the stoichiometric coefficients for each reactant and product.

    Let aa, bb, and cc be the coefficients for Fe\text{Fe}, Cl2\text{Cl}_2, and FeCl3\text{FeCl}_3 respectively.

    aFe+bCl2→cFeCl3a\text{Fe} + b\text{Cl}_2 \rightarrow c\text{FeCl}_3
  2. Write down the balance equations for each element present in the reaction.

    For Iron (Fe): The number of Fe atoms on the reactant side must equal the number of Fe atoms on the product side.

    a=c(1)a = c \quad (1)

    For Chlorine (Cl): The number of Cl atoms on the reactant side must equal the number of Cl atoms on the product side.

    2b=3c(2)2b = 3c \quad (2)
  3. Assign a value to one of the variables to solve the system of equations.

    Let's assume a=1a = 1.

  4. Solve for the other variables using the equations.

    From equation (1):
    If a=1a = 1, then c=1c = 1.

    Substitute c=1c = 1 into equation (2):

    2b=3(1)2b = 3(1) 2b=32b = 3 b=32b = \frac{3}{2}
  5. Convert fractional coefficients to whole numbers.

    The coefficients are a=1a=1, b=32b=\frac{3}{2}, c=1c=1. To get whole numbers, multiply all coefficients by the smallest integer that eliminates the fraction, which is 2.

    a=1×2=2a = 1 \times 2 = 2 b=32×2=3b = \frac{3}{2} \times 2 = 3 c=1×2=2c = 1 \times 2 = 2
  6. Write the balanced chemical equation using the whole number coefficients.

    2Fe+3Cl2→2FeCl32\text{Fe} + 3\text{Cl}_2 \rightarrow 2\text{FeCl}_3
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