This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
To balance the chemical equation wH_2SO_4 + xAl(OH)_3 → yH_2O + zAl_2(SO_4)_3, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Step 1: Balance the Aluminum (Al) atoms. On the reactant side, there are x Al atoms in xAl(OH)_3. On the product side, there are 2z Al atoms in zAl_2(SO_4)_3. So, x = 2z. Step 2: Balance the Sulfate (SO_4) groups. On the reactant side, there are w SO_4 groups in wH_2SO_4. On the product side, there are 3z SO_4 groups in zAl_2(SO_4)_3. So, w = 3z. Step 3: Assign a value to z to find initial coefficients. Let's assume z = 1 (the simplest whole number). Then, from Step 1: x = 2 × 1 = 2. And from Step 2: w = 3 × 1 = 3. Step 4: Substitute the values of w, x, z into the equation and balance Hydrogen (H) and Oxygen (O) atoms to find y. The equation becomes: 3H_2SO_4 + 2Al(OH)_3 → yH_2O + 1Al_2(SO_4)_3 Count H atoms on the reactant side: From 3H_2SO_4: 3 × 2 = 6 H atoms. From 2Al(OH)_3: 2 × 3 = 6 H atoms. Total H atoms on reactant side = 6 + 6 = 12. Count H atoms on the product side: From yH_2O: y × 2 = 2y H atoms. Equating H atoms: 12 = 2y y = 6. Step 5: Verify the balance of Oxygen (O) atoms. Count O atoms on the reactant side: From 3H_2SO_4: 3 × 4 = 12 O atoms. From 2Al(OH)_3: 2 × 3 = 6 O atoms. Total O atoms on reactant side = 12 + 6 = 18. Count O atoms on the product side: From yH_2O (with y=6): 6 × 1 = 6 O atoms. From 1Al_2(SO_4)_3: 1 × (4 × 3) = 12 O atoms. Total O atoms on product side = 6 + 12 = 18. The oxygen atoms are balanced. Step 6: State the final coefficients. The respective values for w, x, y, z are 3, 2, 6, 1. Step 7: Compare with the given options. A: 2,2,6 and 2 B: 2,2,5 and 1 C: 3,2,5 and 2 D: 3,2,6 and 1 The calculated values match option D. The final answer is D.