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Convert the number in base nine to base ten.

Chemistry

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Answer

811\frac{8}{11}

Step-by-step solution

4 steps
  1. Convert the number in base nine to base ten.

    The number 35nine35_{\text{nine}} can be converted to base ten using the formula:

    35nine=(3×91)+(5×90)35_{\text{nine}} = (3 \times 9^1) + (5 \times 9^0) 35nine=(3×9)+(5×1)35_{\text{nine}} = (3 \times 9) + (5 \times 1) 35nine=27+535_{\text{nine}} = 27 + 5 35nine=32ten35_{\text{nine}} = 32_{\text{ten}}
  2. Set up the equation in base ten.

    The given equation is 44p=35nine44p = 35_{\text{nine}}. Substitute the base ten value for 35nine35_{\text{nine}}:

    44p=3244p = 32
  3. Solve for pp.

    To find pp, divide both sides of the equation by 44:

    p=3244p = \frac{32}{44}
  4. Simplify the fraction.

    Both the numerator (32) and the denominator (44) are divisible by 4.

    p=32÷444÷4p = \frac{32 \div 4}{44 \div 4} p=811p = \frac{8}{11}

    The value of pp is 811\boxed{\frac{8}{11}}.

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