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Calculate the degree of ionization of a weak acid with Ka = 10⁻⁴ and initial concentration C = 0.01 M. Also, analyze the provided neutralization reaction based on Brønsted-Lowry theory.

Chemistry

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Answer

1

0.1\text{0.1}

Step-by-step solution

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Here are the solutions for both questions.

Part 1· 3 steps

Degree of ionization

To calculate the degree of ionization (α\alpha) for a weak acid, we can use the approximation α=KaC\alpha = \sqrt{\frac{K_a}{C}}, where KaK_a is the acid dissociation constant and CC is the initial concentration of the acid.

  1. Identify the given values.

    The initial concentration of the acid is C=0.01 MC = 0.01 \text{ M}.
    The acid dissociation constant is Ka=10−4K_a = 10^{-4}.

  2. Apply the approximation formula for the degree of ionization.

    α=KaC\alpha = \sqrt{\frac{K_a}{C}} α=10−40.01\alpha = \sqrt{\frac{10^{-4}}{0.01}}
  3. Calculate the degree of ionization.

    α=10−410−2\alpha = \sqrt{\frac{10^{-4}}{10^{-2}}} α=10−2\alpha = \sqrt{10^{-2}} α=10−1\alpha = 10^{-1} α=0.1\alpha = 0.1

    The degree of ionization is 0.1.

    The final answer is 0.1\boxed{\text{0.1}}.


Part 2

Neutralization reaction statements

The given hypothetical neutralization reaction is:

H2X(aq)+2BOH(aq)⇌B2X(aq)+2H2O(l)\text{H}_2\text{X(aq)} + \text{2BOH(aq)} \rightleftharpoons \text{B}_2\text{X(aq)} + \text{2H}_2\text{O(l)}

Let's analyze each statement based on Brønsted-Lowry acid-base theory:

  • A Brønsted-Lowry acid donates protons (H+\text{H}^+).
  • A Brønsted-Lowry base accepts protons (H+\text{H}^+).
  • A conjugate acid is formed when a base accepts a proton.
  • A conjugate base is formed when an acid donates a proton.

In the reaction:

  • H2X\text{H}_2\text{X} donates protons to BOH\text{BOH} (specifically, its OH−\text{OH}^- part). Thus, H2X\text{H}_2\text{X} acts as an acid.
  • BOH\text{BOH} (or OH−\text{OH}^- from BOH\text{BOH}) accepts protons from H2X\text{H}_2\text{X}. Thus, BOH\text{BOH} acts as a base.
  • When H2X\text{H}_2\text{X} donates protons, its conjugate base is X2−\text{X}^{2-} (which forms B2X\text{B}_2\text{X} with B+\text{B}^+).
  • When OH−\text{OH}^- accepts a proton, its conjugate acid is H2O\text{H}_2\text{O}.

Now, let's evaluate each statement:

  • I. B2X\text{B}_2\text{X} is conjugate acid. B2X\text{B}_2\text{X} is a salt formed from the cation B+\text{B}^+ and the
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