Express all terms with the same base, which is 2.

April 3, 2026Chemistry

ScanSolve AI Answer

April 3, 2026

Answer

128$

Here are the solutions to the mathematics questions:

1) Solve for $x$ : $2^{x} \times 8^{x-1} = 128$

Step 1: Express all terms with the same base, which is 2. $2^x \times (2^3)^{x-1} = 2^7$

Step 2: Apply the exponent rule $(a^m)^n = a^{mn}$ . $2^x \times 2^{3(x-1)} = 2^7$ $2^x \times 2^{3x-3} = 2^7$

Step 3: Apply the exponent rule $a^m \times a^n =

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Quick Answer

1) Solve for x: 2^x × 8^x-1 = 128 Step 1: Express all terms with the same base, which is 2.

Asked on April 3, 2026Chemistry

This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.

ScanSolve AI AnswerAnswered on April 3, 2026

Here are the solutions to the mathematics questions: 1) Solve for x: 2^x × 8^x-1 = 128 Step 1: Express all terms with the same base, which is 2. 2^x × (2^3)^x-1 = 2^7 Step 2: Apply the exponent rule (a^m)^n = a^mn. 2^x × 2^3(x-1) = 2^7 2^x × 2^3x-3 = 2^7 Step 3: Apply the exponent rule $a^m × a^n =