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Express all terms with the same base, which is 2.

Chemistry

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Here are the solutions to the mathematics questions:

1) Solve for xx: 2x×8x−1=1282^{x} \times 8^{x-1} = 128

  1. Express all terms with the same base, which is 2.

    2x×(23)x−1=272^x \times (2^3)^{x-1} = 2^7

  2. Apply the exponent rule (am)n=amn(a^m)^n = a^{mn}.

    2x×23(x−1)=272^x \times 2^{3(x-1)} = 2^7 2x×23x−3=272^x \times 2^{3x-3} = 2^7

  3. Apply the exponent rule $a^m \times a^n =

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