Graph A is at 298 K and Graph B is at 398 K. At 298 K (Graph A), the equilibrium concentration of the product PQ2 is higher (approx. $0.4 mol^{-3

Chemistry
Graph A is at 298 K and Graph B is at 398 K. At 298 K (Graph A), the equilibrium concentration of the product PQ2 is higher (approx. $0.4 mol^{-3

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6.4 Step 1: Analyze the effect of temperature on equilibrium concentrations. Graph A is at 298 K298 \text{ K} and Graph B is at 398 K398 \text{ K}. At 298 K298 \text{ K} (Graph A), the equilibrium concentration of the product PQ2PQ_2 is higher (approx. 0.4mol\cdotdm−30.4 mol\cdotdm^{-3}) and the reactant P2QP_2Q is lower (approx. 0.1mol\cdotdm−30.1 mol\cdotdm^{-3}) compared to 398 K398 \text{ K} (Graph B), where [PQ2][PQ_2] is approx. $0.

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6.4 Step 1: Analyze the effect of temperature on equilibrium concentrations. Graph A is at 298 K and Graph B is at 398 K.

Graph A is at 298 K and Graph B is at 398 K. At 298 K (Graph A), the equilibrium concentration of the product PQ2 is higher (approx. $0.4 mol^{-3
Chemistry

This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.

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Here are the solutions for the remaining questions: 6.4 Step 1: Analyze the effect of temperature on equilibrium concentrations. Graph A is at 298 K and Graph B is at 398 K. At 298 K (Graph A), the equilibrium concentration of the product PQ_2 is higher (approx. 0.4 mol·dm^-3) and the reactant P_2Q is lower (approx. 0.1 mol·dm^-3) compared to 398 K (Graph B), where [PQ_2] is approx. $0.