a)
i) The compound C₆H₁₀ has the general formula CₙH₂ₙ₋₂, which corresponds to an alkyne. With 6 carbon atoms, it is a hexyne.
Name: Hexyne
ii) The compound CH₃CHCH₂ has three carbon atoms and a double bond, making it an alkene.
Name: Propene
b)
i) Step I shows a long chain alkane being converted into ethene (CH₂=CH₂), which is a smaller alkene. This process involves breaking down larger hydrocarbon molecules into smaller, more useful ones.
Name of process: Cracking
ii) To distinguish between ethene (CH₂=CH₂) and ethane (CH₃CH₃), a chemical test for unsaturation can be used.
• Add bromine water (orange/brown) to both compounds.
• Ethene, being an alkene, will undergo an addition reaction with bromine, causing the bromine water to decolorize (turn colorless).
CH2=CH2+Br2→CH2Br−CH2Br
• Ethane, being an alkane, will not react with bromine water under normal conditions, and the orange/brown color will persist.
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