This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
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i. I: Alcohol burner II: Retort stand III: Test tube IV: Delivery tube V: Conical flask ii. • CaCO_3: Calcium carbonate • CuSO_4: Copper(II) sulfate • Ca(OH)_2: Calcium hydroxide iii. a. When wet calcium carbonate is strongly heated, the water will evaporate first. Then, the calcium carbonate will decompose into calcium oxide and carbon dioxide gas. b. The balanced chemical equation is: CaCO_3(s) heat CaO(s) + CO_2(g) iv. a. The anhydrous CuSO_4 (white) will turn blue in the presence of water vapor, indicating that water was produced from the wet CaCO_3. b. The Ca(OH)_2 solution (limewater) will turn milky/cloudy due to the formation of insoluble calcium carbonate precipitate, indicating the presence of carbon dioxide gas. v. Anhydrous cobalt(II) chloride paper (changes from blue to pink in the presence of water). Send me the next one 📸