Identify the substances represented by the letters. (b) Give equations for the reactions in which B is formed from the solution of A on electrolysis and when reacted with E.

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Asked on April 16, 2026Chemistry

This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.

Accepted Answer · 2026-04-16T12:06:38.025Z

You're on a roll — here are the solutions to question 23. Question 23: (a) Identify the substances represented by the letters. A: A soluble solid forming a blue solution that conducts electricity, and whose electrolysis yields a solid (B) and a greenish-yellow gas (C). This indicates Copper(II) chloride (CuCl_2). B: The solid product from the electrolysis of A, which is Copper (Cu). C: The greenish-yellow gas product from the electrolysis of A, which is Chlorine (Cl_2). D: A soluble gas forming a colorless solution, which then forms a pale blue precipitate with A (CuCl_2) that dissolves in excess to form a deep blue solution. This is characteristic of Ammonia (NH_3). E: An insoluble solid that reacts with solution A (CuCl_2) to form B (Copper) and a colorless solution of E^2+ ions. This indicates a metal more reactive than copper, such as Zinc (Zn). (b) Give equations for the reactions in which: (i) Substance B is formed from the solution of A on electrolysis. Substance A is CuCl_2(aq), and substance B is Cu(s). Copper is formed at the cathode during electrolysis. Cu^2+(aq) + 2e^- Cu(s) (ii) Substance B is formed from solution A when reacted with E. Substance A is CuCl_2(aq) (containing Cu^2+ ions), substance B is Cu(s), and substance E is Zn(s). Zinc displaces copper from its salt solution. Zn(s) + Cu^2+(aq) Zn^2+(aq) + Cu(s) (Alternatively: Zn(s) + CuCl_2(aq) ZnCl_2(aq) + Cu(s)) (c) Give one use of gas C. Gas C is Chlorine (Cl_2). One use of gas C is as a disinfectant for water (water purification). (Other uses include: bleaching agent, manufacture of PVC, manufacture of hydrochloric acid). (d) Name the ion responsible for the deep blue solution. The deep blue solution is formed when excess ammonia (D) is added to copper(II) ions (from A). This forms the tetraamminecopper(II) complex ion. The ion responsible is Tetraamminecopper(II) ion. (Formula: [Cu(NH_3)_4]^2+) Question (a) (from the second part of the image): Study the standard electrode potentials for the elements given below and answer the questions that follow. (The letters do not represent the actual symbols of the elements) | Half-cell | E° / Volts | | :-------- | :--------- | | Q²⁺(aq) + 2e⁻ → Q(s) | +2.87 | | R₂(g) + 2e⁻ → 2R⁻(aq) | +1.36 | | S²⁺(aq) + 2e⁻ → S(s) | +1.23 | | T⁺(aq) + e⁻ → T(s) | 0.00 | (i) Identify the strongest oxidizing agent. Give a reason for your answer. The strongest oxidizing agent is the species that has the highest tendency to be reduced (gain electrons), which corresponds to the most positive standard electrode potential (E°). From the table, Q^2+ has the most positive E° value of +2.87 V. The strongest oxidizing agent is Q^2+(aq). Reason: It has the most positive standard electrode potential (E°), indicating the highest tendency to be reduced. (ii) Which two half-cells would produce the highest potential difference when combined? The highest potential difference (e.m.f.) is obtained by combining the half-cell with the most positive E° (cathode) and the half-cell with the most negative E° (anode). Most positive E°: Q^2+/Q (+2.87 V) Most negative E°: T^+/T (0.00 V) The two half-cells are Q²⁺/Q and T⁺/T. (iii) In the space below draw a complete electrochemical cell of the two-half cells mentioned in (ii) above. An electrochemical cell combining Q^2+/Q and T^+/T would consist of: Anode (Oxidation): A T(s) electrode immersed in a solution containing T⁺(aq) ions. Cathode (Reduction): A Q(s) electrode immersed in a solution containing Q²⁺(aq) ions. Salt Bridge: Connecting the two solutions to maintain electrical neutrality. External Circuit: A voltmeter connected between the two electrodes to measure the potential difference, with electrons flowing from the T electrode (anode) to the Q electrode (cathode). [scale=0.8] % Beaker 1 (Anode) (0,0) -- (0,3) -- (3,3) -- (3,0) -- cycle; [fill=gray!30] (0.5,0.5) rectangle (2.5,2.5); % Solution at (1.5,1.5) T⁺(aq); [thick] (1.5,0.5) -- (1.5,2.5); % Electrode [thick, fill=gray] (1.5,2.5) circle (0.1); % Electrode top at (1.5,2.8) T(s); at (1.5,-0.5) Anode; % Beaker 2 (Cathode) (7,0) -- (7,3) -- (10,3) -- (10,0) -- cycle; [fill=gray!30] (7.5,0.5) rectangle (9.5,2.5); % Solution at (8.5,1.5) Q²⁺(aq); [thick] (8.5,0.5) -- (8.5,2.5); % Electrode [thick, fill=gray] (8.5,2.5) circle (0.1); % Electrode top at (8.5,2.8) Q(s); at (8.5,-0.5) Cathode; % Voltmeter (1.5,3) -- (1.5,4) -- (5,4) node[above] Voltmeter -- (8.5,4) -- (8.5,3); (5,4) circle (0.5); at (5,4) V; % Electron flow [->, very thick, blue] (1.5,3.5) -- (4.5,3.5); [->, very thick, blue] (5.5,3.5) -- (8.5,3.5); [above, blue] at (5,3.5) e⁻ flow; % Salt bridge [thick] (2.5,3) arc (0:180:3.5cm and 0.5cm); [thick] (2.5,3) -- (2.5,2.5); [thick] (7.5,3) -- (7.5,2.5); at (5,3.5) [below] Salt Bridge; That's all for today. Send me

Accepted Answer · 2026-04-16T12:06:38.025Z

You're on a roll — here are the solutions to question 23. Question 23: (a) Identify the substances represented by the letters. A: A soluble solid forming a blue solution that conducts electricity, and whose electrolysis yields a solid (B) and a greenish-yellow gas (C). This indicates Copper(II) chloride (CuCl_2). B: The solid product from the electrolysis of A, which is Copper (Cu). C: The greenish-yellow gas product from the electrolysis of A, which is Chlorine (Cl_2). D: A soluble gas forming a colorless solution, which then forms a pale blue precipitate with A (CuCl_2) that dissolves in excess to form a deep blue solution. This is characteristic of Ammonia (NH_3). E: An insoluble solid that reacts with solution A (CuCl_2) to form B (Copper) and a colorless solution of E^2+ ions. This indicates a metal more reactive than copper, such as Zinc (Zn). (b) Give equations for the reactions in which: (i) Substance B is formed from the solution of A on electrolysis. Substance A is CuCl_2(aq), and substance B is Cu(s). Copper is formed at the cathode during electrolysis. Cu^2+(aq) + 2e^- Cu(s) (ii) Substance B is formed from solution A when reacted with E. Substance A is CuCl_2(aq) (containing Cu^2+ ions), substance B is Cu(s), and substance E is Zn(s). Zinc displaces copper from its salt solution. Zn(s) + Cu^2+(aq) Zn^2+(aq) + Cu(s) (Alternatively: Zn(s) + CuCl_2(aq) ZnCl_2(aq) + Cu(s)) (c) Give one use of gas C. Gas C is Chlorine (Cl_2). One use of gas C is as a disinfectant for water (water purification). (Other uses include: bleaching agent, manufacture of PVC, manufacture of hydrochloric acid). (d) Name the ion responsible for the deep blue solution. The deep blue solution is formed when excess ammonia (D) is added to copper(II) ions (from A). This forms the tetraamminecopper(II) complex ion. The ion responsible is Tetraamminecopper(II) ion. (Formula: [Cu(NH_3)_4]^2+) Question (a) (from the second part of the image): Study the standard electrode potentials for the elements given below and answer the questions that follow. (The letters do not represent the actual symbols of the elements) | Half-cell | E° / Volts | | :-------- | :--------- | | Q²⁺(aq) + 2e⁻ → Q(s) | +2.87 | | R₂(g) + 2e⁻ → 2R⁻(aq) | +1.36 | | S²⁺(aq) + 2e⁻ → S(s) | +1.23 | | T⁺(aq) + e⁻ → T(s) | 0.00 | (i) Identify the strongest oxidizing agent. Give a reason for your answer. The strongest oxidizing agent is the species that has the highest tendency to be reduced (gain electrons), which corresponds to the most positive standard electrode potential (E°). From the table, Q^2+ has the most positive E° value of +2.87 V. The strongest oxidizing agent is Q^2+(aq). Reason: It has the most positive standard electrode potential (E°), indicating the highest tendency to be reduced. (ii) Which two half-cells would produce the highest potential difference when combined? The highest potential difference (e.m.f.) is obtained by combining the half-cell with the most positive E° (cathode) and the half-cell with the most negative E° (anode). Most positive E°: Q^2+/Q (+2.87 V) Most negative E°: T^+/T (0.00 V) The two half-cells are Q²⁺/Q and T⁺/T. (iii) In the space below draw a complete electrochemical cell of the two-half cells mentioned in (ii) above. An electrochemical cell combining Q^2+/Q and T^+/T would consist of: Anode (Oxidation): A T(s) electrode immersed in a solution containing T⁺(aq) ions. Cathode (Reduction): A Q(s) electrode immersed in a solution containing Q²⁺(aq) ions. Salt Bridge: Connecting the two solutions to maintain electrical neutrality. External Circuit: A voltmeter connected between the two electrodes to measure the potential difference, with electrons flowing from the T electrode (anode) to the Q electrode (cathode). [scale=0.8] % Beaker 1 (Anode) (0,0) -- (0,3) -- (3,3) -- (3,0) -- cycle; [fill=gray!30] (0.5,0.5) rectangle (2.5,2.5); % Solution at (1.5,1.5) T⁺(aq); [thick] (1.5,0.5) -- (1.5,2.5); % Electrode [thick, fill=gray] (1.5,2.5) circle (0.1); % Electrode top at (1.5,2.8) T(s); at (1.5,-0.5) Anode; % Beaker 2 (Cathode) (7,0) -- (7,3) -- (10,3) -- (10,0) -- cycle; [fill=gray!30] (7.5,0.5) rectangle (9.5,2.5); % Solution at (8.5,1.5) Q²⁺(aq); [thick] (8.5,0.5) -- (8.5,2.5); % Electrode [thick, fill=gray] (8.5,2.5) circle (0.1); % Electrode top at (8.5,2.8) Q(s); at (8.5,-0.5) Cathode; % Voltmeter (1.5,3) -- (1.5,4) -- (5,4) node[above] Voltmeter -- (8.5,4) -- (8.5,3); (5,4) circle (0.5); at (5,4) V; % Electron flow [->, very thick, blue] (1.5,3.5) -- (4.5,3.5); [->, very thick, blue] (5.5,3.5) -- (8.5,3.5); [above, blue] at (5,3.5) e⁻ flow; % Salt bridge [thick] (2.5,3) arc (0:180:3.5cm and 0.5cm); [thick] (2.5,3) -- (2.5,2.5); [thick] (7.5,3) -- (7.5,2.5); at (5,3.5) [below] Salt Bridge; That's all for today. Send me

Identify the substances represented by the letters. (b) Give equations for the reactions in which B is formed from the solution of A on electrolysis and when reacted with E.

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Identify the substances represented by the letters. (b) Give equations for the reactions in which B is formed from the solution of A on electrolysis and when reacted with E.

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