This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.

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\text{Pb(NO
Here are the answers to your questions:
1) List the Importance of organic chemistry
a) 3 importance for Industry
b) 3 importance for food
c) 3 importance for medicine
d) 3 importance for pharmaceutical
2) Draw the structure of Lead Cyanite and write the equation of reaction
Assumption: "Lead Cyanite" is interpreted as Lead(II) Cyanide, , as "Cyanite" is not a standard chemical term for a lead compound.
i) Draw the structure of Lead Cyanide Lead(II) cyanide is an ionic compound. It consists of lead(II) cations () and cyanide anions (). The cyanide ion is linear, with the negative charge primarily on the carbon atom. In the solid state, it forms a polymeric network where lead ions are coordinated by multiple cyanide ions. A simplified representation showing the ions is: In a more detailed structural representation, the cyanide ions bridge between lead ions, forming a polymeric chain or network. For example, showing the connectivity: This indicates a polymeric structure where cyanide ions act as bridging ligands.
ii) Write the equation of reaction The formation of Lead(II) Cyanide can occur through a precipitation reaction between a soluble lead(II) salt (e.g., lead(II) nitrate) and a soluble cyanide salt (e.g., potassium cyanide).
Step 1: Write the reactants and products. Lead(II) nitrate reacts with potassium cyanide to form lead(II) cyanide and potassium nitrate.
Step 2: Write the unbalanced chemical equation.
Step 3: Balance the chemical equation. To balance the cyanide ions, we need 2 moles of KCN. This will also balance the potassium and nitrate ions. \text{Pb(NO_3)_2 (aq) + 2KCN (aq) \rightarrow Pb(CN)_2 (s) + 2KNO_3 (aq)}
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This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.