Calculate the moles of NaOH used in the titration.
This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
Here's how to solve the problem:
Step 1: Calculate the moles of $\text{NaOH}$ used in the titration.
The volume of $\text{NaOH}$ is given in $\text{cm}^3$, so convert it to $\text{dm}^3$:
$$ \text{Volume of NaOH} = 30 \text{ cm}^3 = 0.030 \text{ dm}^3 $$
Now, calculate the moles of $\text{NaOH}$:
$$ \text{Moles of NaOH} = \text{Concentration} \times \text{Volume} $$
$$ \text{Moles of NaOH} = 0.025 \text{ mol dm}^{-3} \times 0.030 \text{ dm}^3 = 0.00075 \text{ mol} $$
**Step 2: Calculate the moles of unreacted $\text{H}_2\text{SO}_4$.
