Calculate the moles of NaOH used in the titration.

The volume of $\text{NaOH}$ is given in $\text{cm}^3$, so convert it to $\text{dm}^3$:

$$\text{Volume of NaOH} = 30 \text{ cm}^3 = 0.030 \text{ dm}^3$$

Now, calculate the moles of $\text{NaOH}$:

$$\text{Moles of NaOH} = \text{Concentration} \times \text{Volume}$$ $$\text{Moles of NaOH} = 0.025 \text{ mol dm}^{-3} \times 0.030 \text{ dm}^3 = 0.00075 \text{ mol}$$