Number and name the above ☝️ compound

The compound contains a carboxylic acid ($\text{-COOH}$) group, which is the highest priority functional group. We identify the longest continuous carbon chain that includes this group.
Starting from the carbon of the $\text{-COOH}$ group (C1):
$\text{C1: -COOH}$
$\text{C2: -CH}_2\text{-}$
$\text{C3: -CH-}$ (attached to $\text{Br}$ and $\text{CH}_3$)
$\text{C4: -CH}_2\text{-}$
$\text{C5: -C-}$ (attached to $\text{F}$ and $\text{OH}$)
$\text{C6: -CH-}$ (attached to $\text{CH}_3$)
$\text{C7: -CH}_3$
The longest chain containing the carboxylic acid group has 7 carbons. Therefore, the parent name is heptanoic acid.

The carbon of the $\text{-COOH}$ group is always designated as C1.

• At C3: Bromine ($\text{Br}$) and a Methyl ($\text{CH}_3$) group.
• At C5: Fluorine ($\text{F}$) and a Hydroxyl ($\text{OH}$) group.
• At C6: A Methyl ($\text{CH}_3$) group.

List the substituents in alphabetical order. Prefixes like "di-" are ignored for alphabetical ordering.
The substituents are:

• Bromo (at C3)
• Fluoro (at C5)
• Hydroxy (at C5)
• Methyl (at C3 and C6, so 3,6-dimethyl)

Arranging them alphabetically: Bromo, Fluoro, Hydroxy, Dimethyl.

The full IUPAC name is: