This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
Here are the solutions to the questions based on the provided image. --- Question 1: State the observations made when Sulphur (IV) Oxide is bubbled through the following: Sulphur (IV) oxide (SO_2) is a reducing agent. It will reduce the oxidizing agents listed below. a) Acidified Potassium Dichromate (VI) Potassium dichromate (VI) solution is orange. SO_2 reduces Cr^6+ (orange) to Cr^3+ (green). Observation: The orange solution turns green. b) Bromine water Bromine water is orange/yellow/brown. SO_2 reduces Br_2 (orange/yellow/brown) to Br^- (colorless). Observation: The orange/yellow/brown solution turns colorless. c) Nitric (V) acid Nitric (V) acid is an oxidizing agent. SO_2 is oxidized to sulfuric acid, while nitric acid is reduced, typically producing nitrogen dioxide gas. Observation: Brown fumes (of nitrogen dioxide, NO_2) are produced. d) Acidified Potassium Manganate (VII) Potassium manganate (VII) solution is purple. SO_2 reduces Mn^7+ (purple) to Mn^2+ (colorless). Observation: The purple solution turns colorless. e) Iron (III) Chloride solution Iron (III) chloride solution is yellow/brown. SO_2 reduces Fe^3+ (yellow/brown) to Fe^2+ (pale green). Observation: The yellow/brown solution turns pale green. --- Question 2: The question states: "Figure 1 is a flow chart which shows various reactions starting with hydrogen and nitrogen. Study it and answer the questions that follow." Unfortunately, Figure 1 (the flowchart) is completely unreadable in the provided image. Therefore, I cannot answer any questions related to it.