Here's the solution to question 24:
To calculate the percentage composition, we use the formula:
Percentageofelement=MolarmassofcompoundTotalmassofelementincompound×100%
We will use the following atomic masses: H=1.0, C=12.0, N=14.0, O=16.0, Na=23.0, Mg=24.3, S=32.1, Cl=35.5, Ca=40.1, Co=58.9, Cu=63.5.
a) Calculate the percentage of each element in the following compounds:
i) Calcium carbonate, CaCO3
Step 1: Calculate the molar mass of CaCO3.
MolarmassofCaCO3=40.1(Ca)+12.0(C)+(3×16.0(O))=40.1+12.0+48.0=100.1g/mol
Step 2: Calculate the percentage of each element.
PercentageofCa=100.140.1×100%=40.06%
PercentageofC=100.112.0×100%=11.99%
PercentageofO=100.148.0×100%=47.95%
The percentages are: Ca:40.06%,C:11.99%,O:47.95%.
ii) Ethanol, C2H5OH (or C2H6O)
Step 1: Calculate the molar mass of C2H6O.
MolarmassofC2H6O=(2×12.0(C))+(6×1.0(H))+16.0(O)=24.0+6.0+16.0=46.0g/mol
Step 2: Calculate the percentage of each element.
PercentageofC=46.024.0×100%=52.17%
PercentageofH=46.06.0×100%=13.04%
PercentageofO=46.016.0×100%=34.78%
The percentages are: C:52.17%,H:13.04%,O:34.78%.
iii) Hydrated copper sulphate, CuSO4⋅5H2O
Step 1: Calculate the molar mass of CuSO4⋅5H2O.
MolarmassofCuSO4=63.5(Cu)+32.1(S)+(4×16.0(O))=63.5+32.1+64.0=159.6g/mol
Molarmassof5H2O=5×((2×1.0(H))+16.0(O))=5×(2.0+16.0)=5×18.0=90.0g/mol