We read your photo as:

Calculate the pH of a buffer solution containing 0.4 M acetic acid and 0.3 M sodium acetate. The pKa of acetic acid is 4.74.

Chemistry

ScanSolve AI Answer

Answer

4.62

Step-by-step solution

5 steps

To calculate the pH of the buffer solution, we will use the Henderson-Hasselbalch equation.

  1. Identify the given values.

    The buffer solution contains acetic acid (CH3COOH\text{CH}_3\text{COOH}) as the weak acid and sodium acetate (CH3COONa\text{CH}_3\text{COONa}) as the source of the conjugate base (CH3COO−\text{CH}_3\text{COO}^-).
    Concentration of weak acid, [CH3COOH]=0.4 M[\text{CH}_3\text{COOH}] = 0.4 \, \text{M}
    Concentration of conjugate base, [CH3COO−]=0.3 M[\text{CH}_3\text{COO}^-] = 0.3 \, \text{M} (since sodium acetate is a strong electrolyte, it dissociates completely)
    pKa\text{pKa} of acetic acid =4.74= 4.74

  2. Write the Henderson-Hasselbalch equation.

    pH=pKa+log⁡10([conjugate base][weak acid])\text{pH} = \text{pKa} + \log_{10}\left(\frac{[\text{conjugate base}]}{[\text{weak acid}]}\right)
  3. Substitute the values into the equation.

    pH=4.74+log⁡10(0.3 M0.4 M)\text{pH} = 4.74 + \log_{10}\left(\frac{0.3 \, \text{M}}{0.4 \, \text{M}}\right)
  4. Calculate the ratio and the logarithm.

    pH=4.74+log⁡10(0.75)\text{pH} = 4.74 + \log_{10}(0.75) pH=4.74+(−0.1249)\text{pH} = 4.74 + (-0.1249) pH=4.74−0.1249\text{pH} = 4.74 - 0.1249 pH=4.6151\text{pH} = 4.6151
  5. Round the pH to an appropriate number of significant figures (usually two decimal places for pH).

    pH≈4.62\text{pH} \approx 4.62

    The pH of the buffer solution is 4.62.

Was this helpful?

Try one yourself

A new problem that tests the same skill.

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp