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Provide the IUPAC names for the following coordination compounds: i. [CrCl2(H2O)4]NO3 ii. [Pd(ONO)2(H2O)2I2] iii. (NH4)3[Fe(CN)6]

Chemistry

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5 parts
i

Dichlorotetraaquachromium(III) nitrate\text{Dichlorotetraaquachromium(III) nitrate}

ii

Diaquadiododinitrito-O-palladium(IV)\text{Diaquadiododinitrito-O-palladium(IV)}

iii

Ammonium hexacyanoferrate(III)\text{Ammonium hexacyanoferrate(III)}

iv

Ammonium hexacyanoferrate(II)\text{Ammonium hexacyanoferrate(II)}

v

Hexaamminechromium(III) bromide\text{Hexaamminechromium(III) bromide}

Step-by-step solution

19 steps

Here are the names for the given coordination compounds:

Part i· 3 steps

[CrCl2(H2O)4]NO3[\text{CrCl}_2(\text{H}_2\text{O})_4]\text{NO}_3

  1. Identify the ligands and their charges.

    Chloro (Cl−\text{Cl}^-) has a -1 charge, aqua (H2O\text{H}_2\text{O}) is neutral. The counter ion is nitrate (NO3−\text{NO}_3^-), which has a -1 charge.

  2. Determine the oxidation state of chromium (Cr).

    x+2(−1)+4(0)=+1x + 2(-1) + 4(0) = +1 x−2=+1x - 2 = +1 x=+3x = +3
  3. Name the complex cation and anion.

    Ligands are named alphabetically: aqua, chloro.
    Name: Dichlorotetraaquachromium(III) nitrate

    Dichlorotetraaquachromium(III) nitrate\boxed{\text{Dichlorotetraaquachromium(III) nitrate}}

Part ii

Diaquadiododinitrito-O-palladium(IV)\text{Diaquadiododinitrito-O-palladium(IV)}

[Pd(ONO)2(H2O)2I2][\text{Pd(ONO)}_2(\text{H}_2\text{O})_2\text{I}_2]

  1. Identify the ligands and their charges.

    Nitrito-O (ONO−\text{ONO}^-) has a -1 charge, aqua (H2O\text{H}_2\text{O}) is neutral, iodo (I−\text{I}^-) has a -1 charge. This is a neutral complex.

  2. Determine the oxidation state of palladium (Pd).

    x+2(−1)+2(0)+2(−1)=0x + 2(-1) + 2(0) + 2(-1) = 0 x−2−2=0x - 2 - 2 = 0 x=+4x = +4
  3. Name the complex.

    Ligands are named alphabetically: aqua, iodo, nitrito-O.
    Name: Diaquadiododinitrito-O-palladium(IV)

    Diaquadiododinitrito-O-palladium(IV)\boxed{\text{Diaquadiododinitrito-O-palladium(IV)}}

Part iii

Ammonium hexacyanoferrate(III)\text{Ammonium hexacyanoferrate(III)}

(NH4)3[Fe(CN)6](\text{NH}_4)_3[\text{Fe(CN)}_6]

  1. Identify the cation and ligands.

    The cation is ammonium (NH4+\text{NH}_4^+). The ligand is cyano (CN−\text{CN}^-), which has a -1 charge.

  2. Determine the charge of the complex anion.

    Since there are three NH4+\text{NH}_4^+ ions, the complex anion must have a -3 charge.

  3. Determine the oxidation state of iron (Fe).

    x+6(−1)=−3x + 6(-1) = -3 x−6=−3x - 6 = -3 x=+3x = +3
  4. Name the complex.

    The metal in an anionic complex ends with "-ate".
    Name: Ammonium hexacyanoferrate(III)

    Ammonium hexacyanoferrate(III)\boxed{\text{Ammonium hexacyanoferrate(III)}}

Part iv

Ammonium hexacyanoferrate(II)\text{Ammonium hexacyanoferrate(II)}

(NH4)4[Fe(CN)6](\text{NH}_4)_4[\text{Fe(CN)}_6]

  1. Identify the cation and ligands.

    The cation is ammonium (NH4+\text{NH}_4^+). The ligand is cyano (CN−\text{CN}^-), which has a -1 charge.

  2. Determine the charge of the complex anion.

    Since there are four NH4+\text{NH}_4^+ ions, the complex anion must have a -4 charge.

  3. Determine the oxidation state of iron (Fe).

    x+6(−1)=−4x + 6(-1) = -4 x−6=−4x - 6 = -4 x=+2x = +2
  4. Name the complex.

    The metal in an anionic complex ends with "-ate".
    Name: Ammonium hexacyanoferrate(II)

    Ammonium hexacyanoferrate(II)\boxed{\text{Ammonium hexacyanoferrate(II)}}

Part v

Hexaamminechromium(III) bromide\text{Hexaamminechromium(III) bromide}

[Cr(NH3)6]Br3[\text{Cr(NH}_3)_6]\text{Br}_3

  1. Identify the ligand and counter ion.

    The ligand is ammine (NH3\text{NH}_3), which is neutral. The counter ion is bromide (Br−\text{Br}^-), which has a -1 charge.

  2. Determine the charge of the complex cation.

    Since there are three Br−\text{Br}^- ions, the complex cation must have a +3 charge.

  3. Determine the oxidation state of chromium (Cr).

    x+6(0)=+3x + 6(0) = +3 x=+3x = +3
  4. Name the complex cation and anion.

    Name: Hexaamminechromium(III) bromide

    Hexaamminechromium(III) bromide\boxed{\text{Hexaamminechromium(III) bromide}}

Part vi· 1 step

[PtCN(ONO)3(NH3)2][\text{PtCN(ONO)}_3(\text{NH}_3)_2]

  1. Identify the ligands and their charges.

    Cyano (CN−\text{CN}^-) has a -1 charge, nitrito-O (ONO−\text{ONO}^-) has a -1 charge, ammine (NH3\text{NH}_3) is neutral. This is a neutral complex.

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