Q1, if 3245 to base six is=xnine find x

To convert a number from any base to base 10, multiply each digit by the base raised to the power of its position, starting from 0 for the rightmost digit before the decimal point.

$$3245_6 = 3 \times 6^3 + 2 \times 6^2 + 4 \times 6^1 + 5 \times 6^0$$ $$3245_6 = 3 \times 216 + 2 \times 36 + 4 \times 6 + 5 \times 1$$ $$3245_6 = 648 + 72 + 24 + 5$$ $$3245_6 = 749_{10}$$

To convert a number from base 10 to another base, repeatedly divide the base 10 number by the new base and record the remainders. The new number is formed by reading the remainders from bottom to top.

$$749 \div 9 = 83 \text{ remainder } 2$$ $$83 \div 9 = 9 \text{ remainder } 2$$ $$9 \div 9 = 1 \text{ remainder } 0$$ $$1 \div 9 = 0 \text{ remainder } 1$$

Reading the remainders from bottom to top, we get $1022_9$.

Since $3245_6 = x_9$, and we found $3245_6 = 1022_9$, then $x$ is 1022.

$$x = 1022$$

The value of $x$ is $\boxed{1022}$.