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Determine the radius of the base of the cone.

Chemistry

ScanSolve AI Answer

Answer

12\frac{1}{2}

Step-by-step solution

6 steps

39) Draw the net of the cone.

  1. Determine the radius of the base of the cone.

    The cone has a slant height L=7 cmL = 7\,\text{cm} and a vertex angle of 60∘60^\circ.
    Consider the isosceles triangle formed by the slant heights and the diameter of the base. Since the two equal sides are 7 cm7\,\text{cm} and the angle between them is 60∘60^\circ, this is an equilateral triangle.
    Therefore, the diameter of the base is 7 cm7\,\text{cm}.
    The radius of the base r=diameter2=72 cm=3.5 cmr = \frac{\text{diameter}}{2} = \frac{7}{2}\,\text{cm} = 3.5\,\text{cm}.

  2. Determine the angle of the sector for the lateral surface.

    The radius of the sector is the slant height L=7 cmL = 7\,\text{cm}.
    The arc length of the sector is equal to the circumference of the base circle.
    Circumference C=2πr=2π(3.5 cm)=7π cmC = 2\pi r = 2\pi (3.5\,\text{cm}) = 7\pi\,\text{cm}.
    The angle θ\theta of the sector (in degrees) is given by the formula:

    θ=rL×360∘\theta = \frac{r}{L} \times 360^\circ θ=3.5 cm7 cm×360∘\theta = \frac{3.5\,\text{cm}}{7\,\text{cm}} \times 360^\circ θ=12×360∘\theta = \frac{1}{2} \times 360^\circ θ=180∘\theta = 180^\circ
  3. Describe the net.

    The net of the cone consists of two parts:

    • A circular base with a radius of 3.5 cm3.5\,\text{cm}.
    • A sector of a circle with a radius of 7 cm7\,\text{cm} and an angle of 180∘180^\circ (a semicircle).

    40) Maureen tossed a die once. Determine the probability that she obtained an even number.

  4. Identify the sample space.

    When a standard die is tossed once, the possible outcomes are the integers from 1 to 6.
    The sample space S={1,2,3,4,5,6}S = \{1, 2, 3, 4, 5, 6\}.
    The total number of possible outcomes is n(S)=6n(S) = 6.

  5. Identify the favorable outcomes.

    We are looking for the probability of obtaining an even number. The even numbers in the sample space are {2,4,6}\{2, 4, 6\}.
    The number of favorable outcomes is n(E)=3n(E) = 3.

  6. Calculate the probability.

    The probability P(E)P(E) of an event EE is given by the formula:

    P(E)=Number of favorable outcomesTotal number of possible outcomesP(E) = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}} P(even number)=n(E)n(S)P(\text{even number}) = \frac{n(E)}{n(S)} P(even number)=36P(\text{even number}) = \frac{3}{6} P(even number)=12P(\text{even number}) = \frac{1}{2}

    The probability that she obtained an even number is 12\frac{1}{2}.

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