This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
Here are the solutions to the given questions:
1. $\log e^2$
Step 1: Recognize that $\log e^2$ implies a natural logarithm, meaning the base is $e$. So, $\log e^2 = \log_e e^2$.
Step 2: Apply the logarithm property $\log_b (x^y) = y \log_b x$.
$$ \log_e e^2 = 2 \log_e e $$
Step 3: Apply the logarithm property $\log_b b = 1$.
$$ 2 \log_e e = 2 \times 1 $$
$$ = 2 $$
The value of $\log e^2$ is $\boxed{\text{2}}$.
2. $\tan 45^\circ$
Step 1: Recall the standard trigonometric value for $\tan 45^\circ$.
Alternatively, use the definition $\tan \theta = \frac{\sin \theta}{\cos \theta}$.
We know that $\sin 45^\circ = \frac{\sqrt{2}}{2}$ and $\cos 45^\circ = \frac{\sqrt{2}}{2}$.
Step 2: Substitute the values into the formula.
$$ \tan 45^\circ = \frac{\sin 45^\circ}{\cos 45^\circ} = \frac{\frac{\sqrt{2}}{2}}{\frac{\sqrt{2}}{2}} $$
Step 3: Simplify the expression.
$$ = 1 $$
The value of $\tan 45^\circ$ is $\boxed{\text{1}}$.
Recognize that e^2 implies a natural logarithm, meaning the base is e. So, e^2 = _e e^2.
|Chemistry
Recognize that e^2 implies a natural logarithm, meaning the base is e. So, e^2 = _e e^2.
ScanSolve AI Answer
Here are the solutions to the given questions:
loge2
Step 1: Recognize that loge2 implies a natural logarithm, meaning the base is e. So, loge2=logee2.
Step 2: Apply the logarithm property logb(xy)=ylogbx.
logee2=2logee
Step 3: Apply the logarithm property logbb=1.
2logee=2×1=2
The value of loge2 is 2.
tan45∘
Step 1: Recall the standard trigonometric value for tan45∘.
Alternatively, use the definition tanθ=cosθsinθ.
We know that sin45∘=22 and cos45∘=22.
Step 2: Substitute the values into the formula.
tan45∘=cos45∘sin45∘=2222
Step 3: Simplify the expression.
=1
The value of tan45∘ is 1.
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