Relative atomic mass of an element Q is 14.0037.Q has two isotopes.15^Q makes up 0.37% of all the atoms.calculate the mass number of the second isotope of element Q

Chemistry

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Answer

14\text{14}

Step-by-step solution

4 steps
  1. Understand the formula for relative atomic mass.

    The relative atomic mass (Ar) of an element is the weighted average of the mass numbers of its isotopes, taking into account their natural abundances.
    For two isotopes, the formula is:

    Ar=(mass number of isotope 1×abundance of isotope 1)+(mass number of isotope 2×abundance of isotope 2)\text{Ar} = (\text{mass number of isotope 1} \times \text{abundance of isotope 1}) + (\text{mass number of isotope 2} \times \text{abundance of isotope 2})

    The abundances are usually expressed as decimals (percentage divided by 100).

  2. Identify the given values.

    • Relative atomic mass of Q (ArQ\text{Ar}_{\text{Q}}) = 14.0037
    • Isotope 1: 15Q^{15}\text{Q}
      • Mass number of isotope 1 = 15
      • Abundance of isotope 1 = 0.37% = 0.37100=0.0037\frac{0.37}{100} = 0.0037
    • Isotope 2: Let its mass number be xx.
      • Abundance of isotope 2 = ?
  3. Calculate the abundance of the second isotope.

    Since there are only two isotopes, their abundances must sum to 100%.
    Abundance of isotope 2 = 100% - Abundance of isotope 1
    Abundance of isotope 2 = 100% - 0.37% = 99.63%
    As a decimal, abundance of isotope 2 = 99.63100=0.9963\frac{99.63}{100} = 0.9963

  4. Substitute the values into the relative atomic mass formula and solve for xx.

    14.0037=(15×0.0037)+(x×0.9963)14.0037 = (15 \times 0.0037) + (x \times 0.9963) 14.0037=0.0555+0.9963x14.0037 = 0.0555 + 0.9963x

    Subtract 0.0555 from both sides:

    14.0037−0.0555=0.9963x14.0037 - 0.0555 = 0.9963x 13.9482=0.9963x13.9482 = 0.9963x

    Divide by 0.9963:

    x=13.94820.9963x = \frac{13.9482}{0.9963} x=14.0000x = 14.0000

    The mass number must be a whole number.

    The mass number of the second isotope is 14\text{14}.

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