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Calculate the relative atomic mass of Neon given the isotopic masses and abundances.

Chemistry

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Answer

20.179 amu20.179 \text{ amu}

Step-by-step solution

3 steps
  1. Identify the isotopes and their abundances.

    The element is Neon (Ne) with three isotopes:

    • 20Ne^{20}\text{Ne} has an isotopic mass of 20 amu and an abundance of 90.92%90.92\%.
    • 21Ne^{21}\text{Ne} has an isotopic mass of 21 amu and an abundance of 0.26%0.26\%.
    • 22Ne^{22}\text{Ne} has an isotopic mass of 22 amu and an abundance of 8.82%8.82\%.
  2. Convert the percentage abundances to fractional abundances.

    • For 20Ne^{20}\text{Ne}: 90.92100=0.9092\frac{90.92}{100} = 0.9092
    • For 21Ne^{21}\text{Ne}: 0.26100=0.0026\frac{0.26}{100} = 0.0026
    • For 22Ne^{22}\text{Ne}: 8.82100=0.0882\frac{8.82}{100} = 0.0882
  3. Calculate the relative atomic mass using the formula

    Relative Atomic Mass = ∑(isotopic mass×fractional abundance)\sum (\text{isotopic mass} \times \text{fractional abundance})

    Relative Atomic Mass=(20×0.9092)+(21×0.0026)+(22×0.0882)\text{Relative Atomic Mass} = (20 \times 0.9092) + (21 \times 0.0026) + (22 \times 0.0882) Relative Atomic Mass=18.184+0.0546+1.9404\text{Relative Atomic Mass} = 18.184 + 0.0546 + 1.9404 Relative Atomic Mass=20.179\text{Relative Atomic Mass} = 20.179

    The relative atomic mass of Neon is 20.179 amu20.179 \text{ amu}.

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