Calculate the relative molecular masses (M,) of the following substances: 1. Water (H 2. Carbon Dioxide (CO2)…

Question

Calculate the relative molecular masses (M,) of the following substances: 1. Water (H 2. Carbon Dioxide (CO2) 3. Methane (CH4) 4. Glucose (C6H12O6). For reference, the atomic masses are approximately: H = 1; O = 16; C = 12

ScanSolve AI Tutor · Accepted Answer

You're right, let's continue with Activity 2.3. We've already covered the first three, so here's the solution for Glucose.

To calculate the relative molecular mass ( $M_r$ ), we sum the relative atomic masses ( $A_r$ ) of all atoms in the molecule. We will use the provided approximate relative atomic masses: Hydrogen ( $\text{H}$ ) $= 1$ , Carbon ( $\text{C}$ ) $= 12$ , and Oxygen ( $\text{O}$ ) $= 16$ .

4) For Glucose ( $\text{C}_6\text{H}_{12}\text{O}_6$ ):

Identify the atoms and their quantities.
The molecule $\text{C}_6\text{H}_{12}\text{O}_6$ contains 6 carbon atoms, 12 hydrogen atoms, and 6 oxygen atoms.
List the relative atomic masses.
$A_r(\text{C}) = 12$
$A_r(\text{H}) = 1$
$A_r(\text{O}) = 16$
Calculate the relative molecular mass.
$M_r(\text{C}_6\text{H}_{12}\text{O}_6) = (6 \times A_r(\text{C})) + (12 \times A_r(\text{H})) + (6 \times A_r(\text{O}))$ $M_r(\text{C}_6\text{H}_{12}\text{O}_6) = (6 \times 12) + (12 \times 1) + (6 \times 16)$ $M_r(\text{C}_6\text{H}_{12}\text{O}_6) = 72 + 12 + 96$ $M_r(\text{C}_6\text{H}_{12}\text{O}_6) = 180$
The relative molecular mass of glucose is $\boxed{\text{180}}$ .

Calculate the relative molecular masses (M,) of the following substances: 1. Water (H 2. Carbon Dioxide (CO2) 3. Methane (CH4) 4. Glucose (C6H12O6). For reference, the atomic masses are approximately: H = 1; O = 16; C = 12

Step-by-step solution

Identify the atoms and their quantities.

List the relative atomic masses.

Calculate the relative molecular mass.

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