Calculate the relative molecular masses (M,) of the following substances: 1. Water (H 2. Carbon Dioxide (CO2) 3. Methane (CH4) 4. Glucose (C6H12O6). For reference, the atomic masses are approximately: H = 1; O = 16; C = 12

You're right, let's continue with Activity 2.3. We've already covered the first three, so here's the solution for Glucose.

To calculate the relative molecular mass ($M_r$), we sum the relative atomic masses ($A_r$) of all atoms in the molecule. We will use the provided approximate relative atomic masses: Hydrogen ($\text{H}$) $= 1$, Carbon ($\text{C}$) $= 12$, and Oxygen ($\text{O}$) $= 16$.

4) For Glucose ($\text{C}_6H_{12}O_6$):

Step 1: Identify the atoms and their quantities. The molecule $\text{C}_6H_{12}O_6$ contains 6 carbon atoms, 12 hydrogen atoms, and 6 oxygen atoms.

Step 2: List the relative atomic masses. $A_r(C) = 12$ $A_r(H) = 1$ $A_r(O) = 16$

Step 3: Calculate the relative molecular mass. $M_r(C_6H_{12}O_6) = (6 \times A_r(C)) + (12 \times A_r(H)) + (6 \times A_r(O))$ $M_r(C_6H_{12}O_6) = (6 \times 12) + (12 \times 1) + (6 \times 16)$ $M_r(C_6H_{12}O_6) = 72 + 12 + 96$ $M_r(C_6H_{12}O_6) = 180$ The relative molecular mass of glucose is $\boxed{180}$.