Rewrite all numbers in the equation with a common base.

The common base for 2, 8, and 128 is 2.
We know that $8 = 2^3$ and $128 = 2^7$.
Substitute these into the equation:

$$2^{(x-3)} \times (2^3)^{(x+2)} = 2^7$$

$$2^{(x-3)} \times 2^{3(x+2)} = 2^7$$ $$2^{(x-3)} \times 2^{(3x+6)} = 2^7$$

$$2^{(x-3) + (3x+6)} = 2^7$$

Combine the exponents on the left side:

$$2^{(x+3x-3+6)} = 2^7$$ $$2^{(4x+3)} = 2^7$$

$$4x+3 = 7$$

Solve for $x$:

$$4x = 7 - 3$$ $$4x = 4$$ $$x = \frac{4}{4}$$ $$x = \boxed{1}$$