Please solve the science aspect for me

Step 1: Determine the concentration of hydroxide ions. Sodium hydroxide ($\text{NaOH}$) is a strong base, meaning it dissociates completely in water. Therefore, the concentration of hydroxide ions $[OH^-]$ is equal to the concentration of the $\text{NaOH}$ solution. Given concentration of $\text{NaOH} = 0.01 \text{ M}$. So, $[OH^-] = 0.01 M = 1 \times 10^{-2} \text{ M}$.

Step 2: Calculate the pOH of the solution. The pOH is calculated using the formula: $\text{pOH} = -\log_{10}[OH^-]$ Substitute the concentration of hydroxide ions: $\text{pOH} = -\log_{10}(1 \times 10^{-2})$ $\text{pOH} = -(-2)$ $\text{pOH} = 2$

Step 3: Calculate the pH of the solution. The relationship between pH and pOH at $25^\circ\text{C}$ is: $\text{pH} + pOH = 14$ Rearrange to solve for pH: $\text{pH} = 14 - \text{pOH}$ Substitute the calculated pOH value: $\text{pH} = 14 - 2$ $\text{pH} = 12$

The final answer is $\boxed{12}$.