Stoichiometry: 4.0 g of H2 reacts completely with O2 to form H2O. What mass of H2O is produced? Show the full worked solution with the final numeric answer.

Chemistry

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Answer

36 g of H2O is produced

Step-by-step solution

6 steps

When 4.0 g of H2 reacts completely with O2, 36 g of H2O is produced.

Full Worked Solution:

  1. Write the balanced chemical equation

    The reaction between hydrogen gas (H2) and oxygen gas (O2) to form water (H2O) is:
    2H2(g) + O2(g) → 2H2O(l)

  2. Calculate the molar masses

    • Molar mass of H2 = 2 × 1.008 g/mol = 2.016 g/mol
    • Molar mass of H2O = (2 × 1.008 g/mol) + 15.999 g/mol = 18.015 g/mol
  3. Convert the given mass of H2 to moles

    Moles of H2 = Mass of H2 / Molar mass of H2
    Moles of H2 = 4.0 g / 2.016 g/mol ≈ 1.984 mol H2

  4. Use the mole ratio from the balanced equation to find moles of H2O

    From the balanced equation, 2 moles of H2 produce 2 moles of H2O. This is a 1:1 mole ratio.
    Moles of H2O = Moles of H2
    Moles of H2O ≈ 1.984 mol H2O

  5. Convert moles of H2O to mass

    Mass of H2O = Moles of H2O × Molar mass of H2O
    Mass of H2O = 1.984 mol × 18.015 g/mol
    Mass of H2O ≈ 35.74 g

  6. Round to the correct number of significant figures

    The given mass (4.0 g) has two significant figures. Therefore, the final answer should also be rounded to two significant figures.
    Mass of H2O ≈ 36 g

    Final Answer: 36 g of H2O is produced.

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