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What are the answers to the following chemistry exam questions covering isotopes, atomic models, and electron capacities?

Chemistry

ScanSolve AI Answer

Here are the answers to your chemistry exam questions:

I. Write True if the statement is correct Or False if it is Incorrect (5 pts)

  1. Isotopes of an element have Similar chemical properties.
    • True
  2. Mendeleev arranged the elements based on increasing order of atomic number.
    • False (He arranged them by increasing atomic mass.)
  3. Isobars are different atoms that have the same mass number.
    • True
  4. Atoms of the same element have the same number of neutrons.
    • False (Isotopes of the same element have different numbers of neutrons.)
  5. The mass of an electron is almost equal to the mass of a proton.
    • False (The mass of an electron is much smaller than that of a proton.)

II. Match column 'A' with column 'B' (5 Pts)

  1. Dalton's Atomic Model →\rightarrow C. Billiard Model
  2. J.J. Thomson Atomic Model →\rightarrow D. Plum-pudding Model
  3. Rutherford's Atomic Model →\rightarrow B. Planetary Model
  4. Bohr's Atomic Model →\rightarrow A. Orbit
  5. Democritus Atomic Model →\rightarrow E. Solid sphere

III. Choose The Correct Answer from the following alternatives (10 pts)

  1. The Energy level in the third principal quantum number can accommodate C. 18\boxed{\text{C. 18}} electrons.

    • Explanation: For a principal quantum number nn, the maximum number of electrons is given by 2n22n^2. For n=3n=3, the maximum is 2(32)=2×9=182(3^2) = 2 \times 9 = 18.
  2. The mass of an atom is concentrated in B. Nucleus\boxed{\text{B. Nucleus}}.

    • Explanation: The nucleus contains protons and neutrons, which account for almost all of an atom's mass.
  3. Which fundamental particle does not present in the hydrogen atom? C. neutron\boxed{\text{C. neutron}}.

    • Explanation: The most common isotope of hydrogen (11^1_1H, protium) has one proton and one electron but no neutrons.
  4. What is the average atomic mass of an element which Isotopic composition is 90% of 20^{20}X and 10% of 22^{22}X? D. 20.2\boxed{\text{D. 20.2}}.

    • Calculation: Average atomic mass=(0.90×20)+(0.10×22)=18+2.2=20.2\text{Average atomic mass} = (0.90 \times 20) + (0.10 \times 22) = 18 + 2.2 = 20.2
  5. Nucleus was discovered by B. Rutherford\boxed{\text{B. Rutherford}}.

    • Explanation: Ernest Rutherford discovered the atomic nucleus through his gold foil experiment.
  6. 1s22s22p63s23p41s^2 2s^2 2p^6 3s^2 3p^4 is an electronic configuration of D. 18Ar\boxed{\text{D. }_{18}\text{Ar}}.

    • Explanation: The given electron configuration has 2+2+6+2+4=162+2+6+2+4 = 16 electrons, which corresponds to Sulfur (S). However, Sulfur is not an option. Assuming there is a typo in the question and the configuration should have been 1s22s22p63s23p61s^2 2s^2 2p^6 3s^2 3p^6 (18 electrons), then it would correspond to Argon (Ar).
  7. How many Protons, electrons and neutrons are found in an atom of 3580_{35}^{80}Br respectively? C. 35, 35, 45\boxed{\text{C. 35, 35, 45}}.

    • Explanation:
      • Atomic number (Z) = 35, so there are 35 protons.
      • For a neutral atom, the number of electrons equals the number of protons, so there are 35 electrons.
      • Mass number (A) = 80.
      • Number of neutrons = A - Z = 80−35=4580 - 35 = 45.
  8. An element has the valence shell electron configuration of 2s22p32s^2 2p^3 to which group and period does it belong? B. VA and 2\boxed{\text{B. VA and 2}}.

    • Explanation:
      • The highest principal quantum number is 2, so it belongs to Period 2.
      • The total number of valence electrons is 2+3=52+3=5. Elements with 5 valence electrons are in Group VA (or Group 15).
  9. The earliest of the attempts to classify elements was that of D. Dobereiner’s triads\boxed{\text{D. Dobereiner's triads}}.

    • Explanation: Dobereiner's triads (1829) were among the first attempts to group elements with similar properties.
  10. How many elements

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