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The following equation represents the reaction for the preparation of ethene from ethanol:

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2 parts
a

Concentrated sulfuric acid\text{Concentrated sulfuric acid}

b

Dehydration\text{Dehydration}

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Here's the solution to question 8:

8) The following equation represents the reaction for the preparation of ethene from ethanol:

C2H5OH(l)→AC2H4(g)+H2O(l)\text{C}_2\text{H}_5\text{OH}(\text{l}) \xrightarrow{\text{A}} \text{C}_2\text{H}_4(\text{g}) + \text{H}_2\text{O}(\text{l})

Part a· 2 steps

Name reagent A.

  1. Analyze the reaction.

    Ethanol (C2H5OH\text{C}_2\text{H}_5\text{OH}) is converted to ethene (C2H4\text{C}_2\text{H}_4) and water (H2O\text{H}_2\text{O}). This is a dehydration reaction, where a molecule of water is removed from the alcohol.

  2. Identify a common dehydrating agent used for this conversion.

    Concentrated sulfuric acid is a strong dehydrating agent often used to convert alcohols to alkenes.

    • Reagent A: Concentrated sulfuric acid\boxed{\text{Concentrated sulfuric acid}}

Part b

Dehydration\text{Dehydration}

Name the process by which ethene is produced in the reaction represented by the equation.

  1. Observe that a water molecule is removed from the ethanol molecule to form ethene.

  2. Recall the term for a reaction that involves the removal of water.

    The process of removing a water molecule from a compound is called dehydration.

    • Process: Dehydration\boxed{\text{Dehydration}}
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