This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
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Hey kamauedwin611, good to see you again. Here are the solutions to the questions based on the image provided. 1) Name the method that can be used to separate T1 and T3 from a mixture of the two. From the table: • T1 is miscible with T2. • T1 is miscible with T4. • T2 is miscible with T3. • T2 is immiscible with T4. The question asks to separate T1 and T3. The table does not directly state the miscibility of T1 and T3. However, it states that T1 is miscible with T2, and T2 is miscible with T3. This implies that T1 and T3 are likely miscible. If two liquids are miscible, they can be separated by fractional distillation if their boiling points are sufficiently different. a) (i) The method used to separate miscible liquids with different boiling points is fractional distillation. Fractional distillation a) (ii) Describe how a mixture of T2 and T4 can be separated. From the table, T2 is immiscible with T4. Immiscible liquids form separate layers and can be separated based on their density. Step 1: Pour the mixture of T2 and T4 into a separating funnel. Step 2: Allow the mixture to settle. Two distinct layers will form due to the immiscibility of the liquids. Step 3: Open the tap of the separating funnel and carefully drain the denser liquid (the bottom layer) into a beaker. Step 4: Close the tap when the interface between the two liquids reaches the tap. The less dense liquid (the top layer) will remain in the separating funnel and can be collected separately. 3. (a) Give the systematic names of the following compounds. a) (i) The compound is given as CH_3-C(CH_2)CH_3. This can be rewritten as CH_3-C(CH_2CH_3)-CH_3. This is a branched alkane. Step 1: Identify the longest continuous carbon chain. The longest chain has 4 carbons (a butane chain). CH_3-CH_2-C(CH_3)-CH_3 (The CH_2 group is part of an ethyl group, making the chain longer than 3 carbons if counted correctly). Let's redraw the structure to be clear: & CH_3 \\ & | \\ CH_3&-C-CH_3 \\ & | \\ & CH_2 \\ & | \\ & CH_3 The longest chain is 4 carbons long (butane). Step 2: Number the carbon chain to give the substituent the lowest possible number. If we number from the top CH_3 or bottom CH_3, the central carbon is carbon 2. The substituent is a methyl group (CH_3). Step 3: Name the compound. The methyl group is on the second carbon. The name is 2-methylbutane. 2-methylbutane a) (ii) The compound is CH_3CH_2CCH. This is an alkyne. Step 1: Identify the longest continuous carbon chain containing the triple bond. There are 4 carbons in the chain. The parent alkane is butane. Step 2: Identify the functional group. There is a triple bond, so it is an alkyne. Step 3: Number the carbon chain to give the triple bond the lowest possible number. Numbering from the right (where the triple bond is): CH_3-CH_2-C The triple bond starts at carbon 1. Step 4: Name the compound. The name is but-1-yne or 1-butyne. But-1-yne a) (iii) The compound is H_2C=CH-C=CH_2. This is a diene. Step 1: Identify the longest continuous carbon chain containing both double bonds. There are 4 carbons in the chain. The parent alkane is butane. Step 2: Identify the functional groups. There are two double bonds, so it is a diene. Step 3: Number the carbon chain to give the double bonds the lowest possible numbers. Numbering from either end gives the double bonds at positions 1 and 3. H_2C=CH-C=CH_2 1 2 3 4 The double bonds are at carbon 1 and carbon 3. Step 4: Name the compound. The name is buta-1,3-diene. Buta-1,3-diene Send me the next one 📸