This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
Morning tahellemadenko01 — let's get this done. a) Elements in the same group have similar chemical properties. From the table, C and F are both in Group I. Therefore, elements with similar chemical properties are C and F. b) Transition metals are located in the d-block of the periodic table, typically between Group II and Group III (or Groups 3-12). Based on its position spanning across the middle of the third period, G is a transition metal. c) Elements that hardly form compounds are noble gases, which are found in Group VIII. From the table, E is in Group VIII. d) Element B is in Group IV. Hydrogen is in Group I. i) Element B (Group IV) has 4 valence electrons and forms 4 bonds. Hydrogen has 1 valence electron and forms 1 bond. The formula of the compound is BH_4. ii) B is a non-metal and hydrogen is a non-metal. The bond formed between two non-metals is a covalent bond. iii) Dot and cross diagram for BH_4: B is the central atom with 4 valence electrons (represented by dots). Each H atom has 1 valence electron (represented by crosses). Each H forms a single covalent bond with B. c H \\ × \\ H · ×B · H \\ · \\ H More accurately, showing shared pairs: c H \\ × \\ H × ·B · × H \\ · \\ H Each bond is a shared pair of electrons, one from B and one from H. c H \\ × · \\ H × · B · × H \\ × · \\ H e) Element D occurs naturally as D^10 and D^12 in the ratio 75 : 25 respectively. i) Atoms of the same element with different mass numbers are called isotopes. ii) Isotopes differ in the number of neutrons. Therefore, the neutron is the sub-atomic particle responsible for this phenomenon. iii) To determine the relative atomic mass of D, we use the weighted average of the masses of its isotopes: Step 1: Convert percentages to decimal abundances. Abundance of D^10 = 75\% = 0.75 Abundance of D^12 = 25\% = 0.25 Step 2: Calculate the relative atomic mass. Relative atomic mass = (mass of D^10 × abundance of D^10) + (mass of D^12 × abundance of D^12) Relative atomic mass = (10 × 0.75) + (12 × 0.25) Relative atomic mass = 7.5 + 3.0 Relative atomic mass = 10.5 Send me the next one 📸