This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
Welcome back Candido — missed you this week. The question asks to determine the percentage of each element present in the salt Potassium Hydrogen Phosphate Pentahydrate (K_2HPO_4 · 5H_2O). The given atomic masses are: K=39, P=31, O=16, H=1. Step 1: Calculate the molar mass of K_2HPO_4 · 5H_2O. The formula contains: • 2 atoms of Potassium (K) • 1 atom of Phosphorus (P) • 4 atoms of Oxygen (O) from HPO_4 • 1 atom of Hydrogen (H) from HPO_4 • 5 molecules of water (5H_2O), which means 5 × 2 = 10 atoms of Hydrogen and 5 × 1 = 5 atoms of Oxygen. Total number of atoms: • K: 2 • P: 1 • O: 4 + 5 = 9 • H: 1 + 10 = 11 Molar mass: M = (2 × 39) + (1 × 31) + (9 × 16) + (11 × 1) M = 78 + 31 + 144 + 11 M = 264 g/mol Step 2: Calculate the mass contribution of each element. • Mass of K: 2 × 39 = 78 g • Mass of P: 1 × 31 = 31 g • Mass of O: 9 × 16 = 144 g • Mass of H: 11 × 1 = 11 g Step 3: Calculate the percentage of each element. Percentage of an element = mass of elementmolar mass of compound × 100\% Percentage of K: \% K = 78 g264 g × 100\% \% K = 29.545\% \% K ≈ 29.55\% Percentage of P: \% P = 31 g264 g × 100\% \% P = 11.742\% \% P ≈ 11.74\% Percentage of O: \% O = 144 g264 g × 100\% \% O = 54.545\% \% O ≈ 54.55\% Percentage of H: \% H = 11 g264 g × 100\% \% H = 4.166\% \% H ≈ 4.17\% The percentages of the elements are: • Potassium (K): 29.55\% • Phosphorus (P): 11.74\% • Oxygen (O): 54.55\% • Hydrogen (H): 4.17\% Send me the next one 📸