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Understand place values in base 5.

Chemistry

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14. Find the value of 2 in 4203five4203_{\text{five}}

  1. Understand place values in base 5.

    In base 5, the place values are powers of 5, starting from the right:
    505^0 (ones place)
    515^1 (fives place)
    525^2 (twenty-fives place)
    535^3 (one hundred twenty-fives place)

  2. Identify the position of the digit 2.

    In the number 4203five4203_{\text{five}}, the digit 2 is in the 525^2 place.

  3. Calculate the value of the digit 2.

    The value of 2 is 2×522 \times 5^2.

    2×52=2×25=502 \times 5^2 = 2 \times 25 = 50 50\boxed{50}

    15. The Executive meeting for DFCU Bank ended at 1:25 pm. If it lasted for 3 hours and 30 minutes, when did it start?

  4. Convert the end time to 24-hour format.

    1:25 pm is 13:25 in 24-hour format.

  5. Subtract the duration of the meeting from the end time.

    First, subtract the hours:
    13:25−3 hours=10:2513:25 - 3 \text{ hours} = 10:25

  6. Subtract the minutes.

    We need to subtract 30 minutes from 10:25. Since 25 minutes is less than 30 minutes, we borrow 1 hour (60 minutes) from the hours.
    10 hours becomes 9 hours, and 25 minutes becomes 25+60=8525 + 60 = 85 minutes.
    Now subtract 30 minutes:
    9:85−30 minutes=9:559:85 - 30 \text{ minutes} = 9:55

  7. Convert the start time back to 12-hour format.

    9:55 in 24-hour format is 9:55 am.

    9:55 am\boxed{9:55 \text{ am}}

    16. Solve the equation 2(k+1)=102(k + 1) = 10

  8. Divide both sides of the equation by 2.

    2(k+1)2=102\frac{2(k + 1)}{2} = \frac{10}{2} k+1=5k + 1 = 5
  9. Subtract 1 from both sides of the equation to isolate kk.

    k+1−1=5−1k + 1 - 1 = 5 - 1 k=4k = 4 4\boxed{4}
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